Triangle RTS is congruent to RQS by AAS postulate of congruent
Step-by-step explanation:
Let us revise the cases of congruence
- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and including angle in the 2nd Δ
- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ ≅ 2 angles and the side whose joining them in the 2nd Δ
- AAS ⇒ 2 angles and one side in the 1st Δ ≅ 2 angles
and one side in the 2nd Δ
- HL ⇒ hypotenuse leg of the 1st right Δ ≅ hypotenuse leg of the 2nd right Δ
∵ SR bisects angle TSQ ⇒ given
∴ ∠TSR ≅ ∠QSR
∴ m∠TSR ≅ m∠QSR
∵ ∠T ≅ ∠Q ⇒ given
∴ m∠T ≅ m∠Q
In two triangles RTS and RQS
∵ m∠T ≅ m∠Q
∵ m∠TSR ≅ m∠QSR
∵ RS is a common side in the two triangle
- By using the 4th case above
∴ Δ RTS ≅ ΔRQS ⇒ AAS postulate
Triangle RTS is congruent to RQS by AAS postulate of congruent
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Answer:
Its already solved, -4+25 does equal -4+25
Step-by-step explanation:
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Answer with explanation:</h2>
As per given , we have
Sample size : n= 5
Degree pf freedom = : df= 5-1=4
Significance level for 90% confidence = 
Using t-value table , t-critical value for 90% confidence:
Margin of error of 
: 
Interpretation : The repair cost will be within $12.39 of the real population mean value 90% of the time.
Answer:
Compass; straightedge.
Step-by-step explanation:
Answer:
See below ~
Step-by-step explanation:
Given :
<u>QRSTU ~ FGCDE</u>
Finding the scale factor :
- Take two corresponding sides in proportion
- RS : GC
- 40 : 12
- <u>10 : 3</u>
Applying the scale factor to find the missing sides :
- FG :
- QR : FG = 10 : 3
- 30/FG = 10/3
- FG = 30/10 x 3
- FG = 3 x 3
- <u>FG = 9</u>
- CD :
- ST : CD = 10 : 3
- 40/CD = 10/3
- CD = 40/10 x 3
- CD = 4 x 3
- <u>CD = 12</u>
- EF :
- UQ : EF = 10 : 3
- 30/EF = 10/3
- EF = 30/10 x 3
- EF = 3 x 3
- <u>EF = 9</u>
