Answer:
No. 2/3 of the space to Grano and 1/3 of the space to Wheatie.
Step-by-step explanation:
Allocating about 57% to Wheatie and 43% to Grano, means to allocate 60(.57)=34.2 ft2 of Wheatie and 60(.43)=25.8 ft2 of Grano. In that case there would be 34.2/.4=85.5≈85 boxes of Wheatie and 25.8/.2=129 boxes of Grano. The total profit would be 129(1)+85(1.35)=$243.75
Best option:
200 Granos boxes and 50 Wheaties boxes on the shelf.
200(.2)=40ft^2 will allocate Granos boxes
50(.4)=20ft^2 will allocate Wheaties boxes.
This means that 40/60=2/3=66.6% of the space will allocate Granos boxes and 20/60=1/3=33.3% of the space will allocate Wheaties boxes.
The total profit would be 200(1)+50(1.35)=$267.5
EXTRA:
This is a optimization problem.
Let X1 be the number of Granos boxes
Let X2 be the number of Wheaties boxes
Objective:
Max Z=1(X1)+1.35(X2)
Subjecto to
0.2(X1)+0.4(X2)<=60,
X1<=200,
X2<=120,
X1,X2>=0.
You can solve it using the simplex method. Check the image for more details.
Answer:
c
Step-by-step explanation:
If there are n rows
And if each row has m seats.
Then the total number of seats shall be n × m.
Here
Number of rows = (c+8)
And number of seats in each row = (4c-1)
Using the concept
Total number of seats
= (c+8)(4c-1)
FOILing or Distributing we get
= c(4c) + c (-1) + 8(4c) +8 (-1)
= 4c² - c + 32 c -8
Combining like terms
=4c² +31c - 8
The expression for total number of seats = 4c² + 31c -8