The center of a circle is located at c(3,-13). the x-axis is tangent to the circle at (3,0). find the equation of the circle.

1 answer:

6 0

Hello :
let : A(3,0)
the ridus is : CA = <span>√((3-3)² +(0+13)²) = 13
</span><span>he equation of the circleis : (x-3)² + (y+13)² = 169</span>

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