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sladkih [1.3K]
3 years ago
6

John has a $1000 bond with a 3% coupon. How much interest will John receive for this bond every 6 months?

Mathematics
2 answers:
Vinil7 [7]3 years ago
7 0

Answer:

..$15.00 every 6 months..

atroni [7]3 years ago
3 0
If a bond cam with 3 % coupon, it means 3 % interest per year

so , if the question asked to count the one received every 6 months, the calculation would be : 

$1000 x 3 % x 6/12

= $15 every 6 months

hope this helps
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If a = 7 and b = 11, what is the measure of ∠B? (round to the nearest tenth of a degree)
Naddik [55]

Answer:

57.5 degrees

Step-by-step explanation:

Assuming this is a triangle

a is adjacent is ∠B

b is opposite of ∠B

Use the inverse tangent equation: tan^{-1} (11/7)

This equals to 57.52880771

3 0
3 years ago
1 - f = -5 the answer has to be 6 (show work) (please)
Anestetic [448]

Answer:

it is 6 because there is no other explanation to 1-f f=6!

Step-by-step explanation:

all i did was look 1 - f = 5 then f equaled 6!

8 0
3 years ago
The tensile strength of a metal part is normally distributed with mean 40 pounds and standard deviation 5 pounds. If 50,000 part
nalin [4]

Answer:

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

7933 parts

b) How many would have a tensile strength in excess of 48 pounds?

2739.95 parts

Step-by-step explanation:

The formula for calculating a z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

a) how many would you expect to fail to meet a minimum specification limit of 35-pounds tensile strength?

z = (x-μ)/σ

x = 35 μ = 40 , σ = 5

z = 35 - 40/5

= -5/-5

= -1

Determining the Probability value from Z-Table:

P(x<35) = 0.15866

Converting to percentage = 15.866%

We are asked how many will fail to meet this specification

We have 50,000 parts

Hence,

15.866% of 50,000 parts will fail to meet the specification

= 15.866% of 50,000

= 7933 parts

Therefore, 7933 parts will fail to meet the specifications.

b) How many would have a tensile strength in excess of 48 pounds?

z = (x-μ)/σ

x = 48 μ = 40 , σ = 5

z = 48 - 40/5

z = 8/5

z = 1.6

P-value from Z-Table:

P(x<48) = 0.9452

P(x>48) = 1 - P(x<48)

1 - 0.9452

= 0.054799

Converting to percentage

= 5.4799%

Therefore, 5.4799% will have an excess of (or will be greater than) 48 pounds

We are asked, how many would have a tensile strength in excess of 48 pounds?

This would be 5.4799% of 50,000 parts

= 5.4799% × 50,000

= 2739.95

Therefore, 2739.95 parts will have a tensile strength excess of 48 pounds

4 0
3 years ago
Do any of them you know
snow_tiger [21]

Answer:

I believe I am correct.

1: slope

2: linear equation

3: y-intercept

4: slope-intercept form

5: y-intercept is (0,6) the slope is -2

6: y-intercept is (0,3.4) the slope is 10/6

7: y-intercept is (0,4) the slope is -4/16

Hope this works for you Jack Jiang.

5 0
3 years ago
(A(X+13)=132 what is A and what is X???
frosja888 [35]

Answer:

X=132-13A/A, A cannot equal 0

A=132/X+13, X cannot equal -13

5 0
3 years ago
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