Question

A baseball player bunts a ball down the first base line. It rolls 33 ft at an angle of 25 Degree with the first base path. The pitcher's mound is 60.5 ft from home plate. How far must he travel to get to the ball? Note that a baseball diamond is a square. The pitcher must run feet. (Round to the nearest foot.)

Answer 1

Answer:

34 ft

Step-by-step explanation:

We are given that

BC=33 ft

AC=60.5 ft

$\angle ACB=45-25=20^{\circ}$

We have to find the distance travel by baseball player to get to the ball.

Cosine law:$c=\sqrt[a^2+b^2-2abcos\gamma}$

Substitute the values then we get

$c=\sqrt{(33)^2+(60.5)^2-2(33)(60.5)cos 25^{\circ}}$

The distance traveled by base player to get to the ball $=33.64\approx 34 ft$

Hence, the distance traveled by base player to get to the ball$=34 ft$