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nirvana33 [79]
3 years ago
5

A machine can stamp 40 envelopes in 8 minutes. How many of these machines, working simultaneously, are required or needed to sta

mp 120 envelopes per minute?
Mathematics
1 answer:
ziro4ka [17]3 years ago
8 0

Divide 40 by 8 minutes to find the quantity per minute for one machine:

40 / 8 = 5 per minute.

One machine does 5 envelopes per minute.

Now divide 120 by 5 to find the number of machines needed:

120 / 5 = 24

24 machines would be needed.

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dusya [7]
(a+15.25)=x cost of each tree
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equatiin all together
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3. Ally has a piece of string that is 6 yards 2 feet long. How many inches of string does she have?​
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Find the product.<br><br>(0.5n 5)2(10n 7) 3
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7 0
4 years ago
Read 2 more answers
Add - 3/x + 7y/x . <br> -4y/2x<br> -3 + 7y/x<br> - 10y/x<br> -3 + 7y/2x
yanalaym [24]

Answer:

-\frac{3}{x} + \frac{7y}{x} = \frac{-3+ 7y}{x}

Step-by-step explanation:

Given

-\frac{3}{x} , \frac{7y}{x}

Required

Add

The statement can be interpreted as:

-\frac{3}{x} + \frac{7y}{x}

Take LCM

-\frac{3}{x} + \frac{7y}{x} = \frac{-3+ 7y}{x}

3 0
3 years ago
An optical inspection system is used to distinguish among different part types. The probability of a correct classification of a
MAVERICK [17]

Answer:

Probability Mass Function:

   x:          0                         1                            2                          3

P(x):          0.000064          0.004608             0.115902             0.884736

Step-by-step explanation:

We are given the following information:

We treat correct classification  as a success.

P(correct classification) = 0.96

Then the number of classification follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 3 and x = 0, 1, 2, 3

We have to evaluate:

P(x = 0)\\= \binom{3}{0}(0.96)^0(1-0.96)^3\\=0.000064

P(x = 1)\\= \binom{3}{1}(0.96)^1(1-0.96)^2\\=0.004608

P(x = 2)\\= \binom{3}{2}(0.96)^2(1-0.96)^1\\=0.115902

P(x = 3)\\= \binom{3}{3}(0.96)^3(1-0.96)^0\\=0.884736

PMF:

   x:          0                         1                            2                          3

P(x):          0.000064          0.004608             0.115902             0.884736

8 0
3 years ago
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