Answer:
which is the first option in the list of possible answers.
Step-by-step explanation:
Recall that the minimum of a parabola generated by a quadratic expression is at the vertex of the parabola, and the formula for the vertex of a quadratic of the general form:
is at
For our case, where we have:
And when x = 1, the value of "y" is:
Recall now that we can write the quadratic in what is called: "vertex form" using the coordinates of the vertex as follows:
Then, for our case:
Then, for the quadratic equal to zero as requested in the problem, we have:
Answer:
Step-by-step explanation:
All lines in the plane are of the form
y = mx+b
<u><em>The intersection with the Y-axis is obtained by replacing x with 0 </em></u>
<u><em>The intersection with the X-axis is obtained by replacing y with 0 </em></u>
If we want that the Y-intercept = -5, then
-5 = m(0)+b
So b = -5
Our temporal equation is then
y = mx-5
If we want that the X-intercept = 7, then
0 = m(7)-5
7m = 5
m = 5/7
So our final equation is
Attached is the graph of the line
