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Snezhnost [94]
3 years ago
7

In 3x−7≤ -2 what is the largest integer value of x in the solution

Mathematics
1 answer:
PtichkaEL [24]3 years ago
8 0

Answer:

X is less than or equal to 1.66666666667

Step-by-step explanation:

3x-7(less than or equal to)-2

-7+7= 0

-2+7=5

3x divided by 3 cancles out

5 divided by 3 = 1.66666666667

x is less than or equal to 1.66666666667

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Prove the following by induction. In each case, n is apositive integer.<br> 2^n ≤ 2^n+1 - 2^n-1 -1.
frutty [35]
<h2>Answer with explanation:</h2>

We are asked to prove by the method of mathematical induction that:

2^n\leq 2^{n+1}-2^{n-1}-1

where n is a positive integer.

  • Let us take n=1

then we have:

2^1\leq 2^{1+1}-2^{1-1}-1\\\\i.e.\\\\2\leq 2^2-2^{0}-1\\\\i.e.\\2\leq 4-1-1\\\\i.e.\\\\2\leq 4-2\\\\i.e.\\\\2\leq 2

Hence, the result is true for n=1.

  • Let us assume that the result is true for n=k

i.e.

2^k\leq 2^{k+1}-2^{k-1}-1

  • Now, we have to prove the result for n=k+1

i.e.

<u>To prove:</u>  2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Let us take n=k+1

Hence, we have:

2^{k+1}=2^k\cdot 2\\\\i.e.\\\\2^{k+1}\leq 2\cdot (2^{k+1}-2^{k-1}-1)

( Since, the result was true for n=k )

Hence, we have:

2^{k+1}\leq 2^{k+1}\cdot 2-2^{k-1}\cdot 2-2\cdot 1\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{k-1+1}-2\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-2

Also, we know that:

-2

(

Since, for n=k+1 being a positive integer we have:

2^{(k+1)+1}-2^{(k+1)-1}>0  )

Hence, we have finally,

2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Hence, the result holds true for n=k+1

Hence, we may infer that the result is true for all n belonging to positive integer.

i.e.

2^n\leq 2^{n+1}-2^{n-1}-1  where n is a positive integer.

6 0
3 years ago
I need help I don't understand this one math is my hardest subject
aksik [14]
In order to name the coordinates, you read the X axis first and then the Y axis. So A would be (-4, 4). B would be (-4, 6). C would be (2, 4). 

They are not congruent because each angle is a different measure. 

Hope this helped! :)
4 0
3 years ago
-9 - (-4) = <br> What does that equal to?
CaHeK987 [17]

Answer:

-5

Step-by-step explanation:

When you subtract a negative you end up adding it instead

5 0
3 years ago
which inequality represents all values of x for which the quotient below is defined?√8x^2 divided by √2x
MA_775_DIABLO [31]

Answer:

The function is defined when x > 0

Step-by-step explanation:

Functions with radicals are only undefined when the value in the radical is negative, because the root of a negative number is imaginary.  

We know the function is undefined when the denominator is equal to zero.  \sqrt{2x} is equal to zero when x=0.

We also know that functions with radicals are undefined when the value in the radicals are negative, because the root of a negative number is imaginary.  .  8x^{2} will always be positive, but 2x is negative when x < 0.

So the function is undefined when x = 0, and when x < 0.

Therefore it is defined when x > 0

5 0
3 years ago
What is 60% out of 40?
Afina-wow [57]

Answer:

24

Step-by-step explanation:

Divide 40 by 10 and multiply your answer by 6

8 0
3 years ago
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