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Snezhnost [94]
2 years ago
7

In 3x−7≤ -2 what is the largest integer value of x in the solution

Mathematics
1 answer:
PtichkaEL [24]2 years ago
8 0

Answer:

X is less than or equal to 1.66666666667

Step-by-step explanation:

3x-7(less than or equal to)-2

-7+7= 0

-2+7=5

3x divided by 3 cancles out

5 divided by 3 = 1.66666666667

x is less than or equal to 1.66666666667

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Answer: supplementary

Step-by-step explanation:

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3 years ago
2x-2y=22 find the value of y when x equals 2
11111nata11111 [884]

Answer:

y = -9

Step-by-step explanation:

Step 1: Substitute x

2(2) - 2y = 22

Step 2: Isolate y

-2y = 18

Step 3: Divide by -2

y = -9

And you have your final answer!

8 0
4 years ago
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Step-by-step explanation:

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3 years ago
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Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to
RUDIKE [14]

Answer:

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75

And for the margin of error we have the following estimation:

ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62

5 0
3 years ago
A help would be greatly appreciated! 
dalvyx [7]
The tree was approximately 40.8ft tall.

You use the equation, a^2+b^2=c^2.
12^2 + 39^2 = x^2, add the results of 12^2 and 39^2 to make 1665 = x^2. You can take the positive root of both sides, 3√185, and it equals 40.80441152, which is rounded to 40.8.
7 0
4 years ago
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