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Rom4ik [11]
3 years ago
12

PLZZ could someone help me out with this and explain

Mathematics
2 answers:
jenyasd209 [6]3 years ago
3 0

Answer:

It would be D because X^2 is different from 3x you would just multiply X^2 by 1 and 3x by 1 to get x^2+3x

anygoal [31]3 years ago
3 0

Answer:

3x³+3x so C

Step-by-step explanation:

Multiply both the given equations

x²(3x) = 3x³

+1(3x)=+3x

Then combine

3x³+3x so C

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7 0
3 years ago
Read 2 more answers
Find all possible values of α+
const2013 [10]

Answer:

\rm\displaystyle  0,\pm\pi

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when <u>tanα+tanβ+tanγ = tanαtanβtanγ</u><u> </u>to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

\rm\displaystyle  \tan( \alpha )  +  \tan( \beta ) =  \tan( \alpha )  \tan( \beta )  \tan( \gamma )  -  \tan( \gamma )

factor out tanγ:

\rm\displaystyle  \tan( \alpha )  +  \tan( \beta ) =   \tan( \gamma ) (\tan( \alpha )  \tan( \beta ) -  1)

divide both sides by tanαtanβ-1 and that yields:

\rm\displaystyle   \tan( \gamma ) =  \frac{ \tan( \alpha )  +  \tan( \beta ) }{ \tan( \alpha )  \tan( \beta )    - 1}

multiply both numerator and denominator by-1 which yields:

\rm\displaystyle   \tan( \gamma ) =   -  \bigg(\frac{ \tan( \alpha )  +  \tan( \beta ) }{ 1 - \tan( \alpha )  \tan( \beta )   } \bigg)

recall angle sum indentity of tan:

\rm\displaystyle   \tan( \gamma ) =   -  \tan( \alpha  +  \beta )

let α+β be t and transform:

\rm\displaystyle   \tan( \gamma ) =   -  \tan( t)

remember that tan(t)=tan(t±kπ) so

\rm\displaystyle   \tan( \gamma ) =    -\tan(   \alpha   +\beta\pm k\pi )

therefore <u>when</u><u> </u><u>k </u><u>is </u><u>1</u> we obtain:

\rm\displaystyle   \tan( \gamma ) =    -\tan(   \alpha   +\beta\pm \pi )

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

\rm\displaystyle   \tan( \gamma ) =    \tan(   -\alpha  -\beta\pm \pi )

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

\rm\displaystyle  \gamma  =      -   \alpha   -  \beta \pm \pi

isolate -α-β to left hand side and change its sign:

\rm\displaystyle \alpha  +  \beta  +   \gamma  =  \boxed{ \pm \pi  }

<u>when</u><u> </u><u>i</u><u>s</u><u> </u><u>0</u>:

\rm\displaystyle   \tan( \gamma ) =    -\tan(   \alpha   +\beta \pm 0 )

likewise by Opposite Angle Identity we obtain:

\rm\displaystyle   \tan( \gamma ) =    \tan(   -\alpha   -\beta\pm 0 )

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

\rm\displaystyle  \gamma  =      -   \alpha   -  \beta \pm 0

isolate -α-β to left hand side and change its sign:

\rm\displaystyle \alpha  +  \beta  +   \gamma  =  \boxed{ 0  }

and we're done!

8 0
3 years ago
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Given cos 0 = 3/5 and 0 is in Quadrant I, what is the value of tan 0 ?
olga_2 [115]

Answer:

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Step-by-step explanation:

cos θ = 3 / 5

cos 53 = 3 / 5

θ = 53

tan θ = sin θ / cos θ

sin 53 = 4 / 5

tan 53 = sin 53 / cos 53

= ( 4 / 5 ) / ( 3 / 5 )

= ( 4 / 5 ) x ( 5 / 3 )

= ( 4 x 5 ) / ( 5 x 3 )

tan 53 = 4 / 3

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What are the main properties of a rectangle <br> Use rectangle (BCDE) to help you .
OleMash [197]

Answer:

it must be number 1

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q<13

Step-by-step explanation:

2q is less than 26 so 1q has to be less than half of 26 or 13.

q<13

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