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artcher [175]
3 years ago
6

Given cos 0 = 3/5 and 0 is in Quadrant I, what is the value of tan 0 ?

Mathematics
1 answer:
olga_2 [115]3 years ago
4 0

Answer:

4 / 3

Step-by-step explanation:

cos θ = 3 / 5

cos 53 = 3 / 5

θ = 53

tan θ = sin θ / cos θ

sin 53 = 4 / 5

tan 53 = sin 53 / cos 53

= ( 4 / 5 ) / ( 3 / 5 )

= ( 4 / 5 ) x ( 5 / 3 )

= ( 4 x 5 ) / ( 5 x 3 )

tan 53 = 4 / 3

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What is the equation of a hyperbola with a = 1 and c = 9? Assume that the transverse axis is horizontal.
rosijanka [135]
C^2-a^2=b^2 b^2=81-36=45 x^2/36-y^2/45=1?
5 0
3 years ago
The drawing below is of a regular pentagon. The measure for each interior angle in a regular pentagon is 108°. Angle A is supple
myrzilka [38]

Answer:

  • 72°

Step-by-step explanation:

<u>The interior and exterior angles are supplementary:</u>

  • A + 108° = 180°
  • A = 180° - 108°
  • A = 72°
6 0
2 years ago
Please help asap!! Thank you
djyliett [7]

Step-by-step explanation:

Hey, there!!

Let's simply work with it,

60° + 2x° + (2x+12)° = 180° { being a linear pair}.

or, 72° + 4x = 180°

4x = 180° - 70°

x =  \frac{108}{4}

Therefore, the value of x is 27°.

Now,

2x° = (2×27)°= 54°

(2x+12)° = 2×27°+12°= 66°.

(x+2)= 27+ 2= 29°

Now, The left angle is 27°.

Therefore, The answer is option A.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

6 0
3 years ago
There are 16 teams in a tournament. if during the first round, each team plays every other team exactly once, how many games wil
jasenka [17]
16x17=272/2=136. That is answer.
5 0
3 years ago
Which of the following are identities? Check all that apply. A. cot2x + 1 = csc2x B. tan2x = 1 - sec2x C. sin2x = 1 + cos2x D. s
kirill115 [55]

I'll assume those are squares.  We know D is an identity:

\sin^2 x + \cos ^2 x = 1

Dividing through by \sin ^2 x

1 + \cot^2 x = \csc^2 x

That's A.

Dividing the original through by \cos ^2 x

\tan^2 x + 1 = \sec^2 x

Not quite B, wrong sign on tangent.  

C has the wrong sign on cosine squared as well.

Identities: A & D
4 0
3 years ago
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