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xxTIMURxx [149]
4 years ago
15

Choose the best definition for the following term: algebraic expression (1 point)

Mathematics
1 answer:
Sphinxa [80]4 years ago
4 0
A number, a variable, or group of number and variables that are added, subtracted, multiplied, or divided
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Harold bought 20 toys for his nieces and nephews. The least expensive toy cost $8.21, and the most expensive toy cost $13.79. Wh
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true

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−3x^ 2 +6x+9=<br> factor
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A water molecule is made up of 3 atoms. One third of the atoms are oxygen and the remaining atoms are hydrogen. If there are 114
Mashcka [7]

Answer:

228 hydrogen atoms

Step-by-step explanation:

In a water molecule,

1/3rd is oxygen atoms, and

2/3rd (1 - 1/3 = 2/3) is hydrogen atoms

If there are 114 water molecules,

Total number of atoms would be:

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Out of these, 2/3rd would be hydrogen atoms, so:

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7 0
4 years ago
g If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds
dezoksy [38]

Answer:

The number of ways to select 5 diamonds and 3 clubs is 368,082.

Step-by-step explanation:

In a standard deck of 52 cards there are 4 suits each consisting of 13 cards.

Compute the probability of selecting 5 diamonds and 3 clubs as follows:

The number of ways of selecting 0 cards from 13 hearts is:

{13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1

The number of ways of selecting 3 cards from 13 clubs is:

{13\choose 3}=\frac{13!}{3!\times(13-3)!} =\frac{13!}{13!\times10!}=286

The number of ways of selecting 5 cards from 13 diamonds is:

{13\choose 5}=\frac{13!}{5!\times(13-5)!} =\frac{13!}{13!\times8!}=1287

The number of ways of selecting 0 cards from 13 spades is:

{13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1

Compute the number of ways to select 5 diamonds and 3 clubs as:

{13\choose0}\times{13\choose3}\times{13\choose5}\times{13\choose0} = 1\times286\times1287\times1=368082

Thus, the number of ways to select 5 diamonds and 3 clubs is 368,082.

6 0
3 years ago
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