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4 years ago

Choose the best definition for the following term: algebraic expression (1 point)

Mathematics

1 answer:

Sphinxa [80]4 years ago

4 0

A number, a variable, or group of number and variables that are added, subtracted, multiplied, or divided

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Harold bought 20 toys for his nieces and nephews. The least expensive toy cost $8.21, and the most expensive toy cost $13.79. Wh

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The logical answer would be d

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3 years ago

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The distance that an object covered in time was measured and recorded in the table below.True/False: The distance covered is dir

Sedaia [141]

Answer:

true

Step-by-step explanation:

did the test

5 0

3 years ago

−3x^ 2 +6x+9=<br> factor

GrogVix [38]

Answer:

the answer in factor form would be

-3(

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3 years ago

A water molecule is made up of 3 atoms. One third of the atoms are oxygen and the remaining atoms are hydrogen. If there are 114

Mashcka [7]

Answer:

228 hydrogen atoms

Step-by-step explanation:

In a water molecule,

1/3rd is oxygen atoms, and

2/3rd (1 - 1/3 = 2/3) is hydrogen atoms

If there are 114 water molecules,

Total number of atoms would be:

3 * 114 = 342 (1 oxygen and 2 hydrogen atoms in 1 water molecule)

Out of these, 2/3rd would be hydrogen atoms, so:

$\frac{2}{3}*342=228$

There would be 228 hydrogen atoms

7 0

4 years ago

g If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds

dezoksy [38]

Answer:

The number of ways to select 5 diamonds and 3 clubs is 368,082.

Step-by-step explanation:

In a standard deck of 52 cards there are 4 suits each consisting of 13 cards.

Compute the probability of selecting 5 diamonds and 3 clubs as follows:

The number of ways of selecting 0 cards from 13 hearts is:

${13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1$

The number of ways of selecting 3 cards from 13 clubs is:

${13\choose 3}=\frac{13!}{3!\times(13-3)!} =\frac{13!}{13!\times10!}=286$

The number of ways of selecting 5 cards from 13 diamonds is:

${13\choose 5}=\frac{13!}{5!\times(13-5)!} =\frac{13!}{13!\times8!}=1287$

The number of ways of selecting 0 cards from 13 spades is:

${13\choose 0}=\frac{13!}{0!\times(13-0)!} =\frac{13!}{13!}=1$

Compute the number of ways to select 5 diamonds and 3 clubs as:

${13\choose0}\times{13\choose3}\times{13\choose5}\times{13\choose0} = 1\times286\times1287\times1=368082$

Thus, the number of ways to select 5 diamonds and 3 clubs is 368,082.

6 0

3 years ago