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3 years ago

Find mabc (2X+14) (x+7)

Mathematics

1 answer:

drek231 [11]3 years ago

6 0

Answer:

Step-by-step explanation: 14

Simplify ——

x :

(2x - ——) - 7

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Something x something x something =70

nadya68 [22]

Here is what the answer to your question is:
7x10x1=70

5 0

3 years ago

Read 2 more answers

Type the correct answer in each box. Spell all words correctly, and use numerals instead of words for numbers.

Andru [333]

Answer:

Nate made a mistake. He should have got 24 as Least common factor.

Step-by-step explanation:

Given number are 8 and 12.

To find the GCF or LCF we have to list multiples.

For LCF

List the multiples of each number until at least one of the multiples appears on all lists.
Find the smallest number that is on all of the lists.
This number is the LCM.

For GCF

List the multiples of each number until at least one of the multiples appears on all lists.
Find the Biggest number that is on all of the lists.
This number is the GCF

The least common multiple of 8 and 12 is 24.

The Greatest common multiply of 8 and 12 is 4.

Hence, Nate is wrong. Nate should have found 24.

[RevyBreeze]

7 0

2 years ago

Which ratio is equivalent to 3/15

Rzqust [24]

Answer:

Step-by-step explanation:

The ratio of 6:30 would be equivalent to it.

4 0

3 years ago

A bag of marbles contains 12 red marbles 8 blue marbles and 5 green marbles. If three marbles are pulled out find each of the pr

worty [1.4K]

Answer: The probability of pulling a red marble is 48%, probability of pulling a blue marble is 32%, probability of pulling a green marble is 20%

and

the probability of pulling three green marbles out with replacement is 0.8%.

Step-by-step explanation: Given that a bag of marbles contains 12 red marbles 8 blue marbles and 5 green marbles.

Let S be the sample space for the experiment of pulling a marble.

Then, n(S) = 12 + 8 + 5 = 25.

Let, E, F and G represents the events of pulling a red marble, a blue marble and a green marble respectively.

The, n(E) = 12, n(F) = 8 and n(G) = 5.

Therefore, the probabilities of each of these three events E, F and G will be

$P(E)=\dfrac{n(E)}{n(S)}=\dfrac{12}{25}=\dfrac{12}{25}\times100\%=48\%,\\\\\\P(F)=\dfrac{n(F)}{n(S)}=\dfrac{8}{25}=\dfrac{8}{25}\times100\%=32\%,\\\\\\P(G)=\dfrac{n(G)}{n(S)}=\dfrac{5}{25}=\dfrac{5}{25}\times100\%=20\%.$

Now, the probability of pulling three green marbles out with replacement is given by

$P(G)\times P(G)\times P(G)=\dfrac{5}{25}\times\dfrac{5}{25}\times \dfrac{5}{25}=\dfrac{1}{125}=\dfrac{1}{125}\times100\%=0.8\%.$

Thus, the probability of pulling a red marble is 48%, probability of pulling a blue marble is 32%, probability of pulling a green marble is 20%

and

the probability of pulling three green marbles out with replacement is 0.8%.

4 0

3 years ago

Dr. Jimenez found that after applying an antibiotic to bacteria, he observed only 90% of the bacteria left in the culture dish e

USPshnik [31]

<span>If the intial count was 100,000 bacteria, after one hour 90% decrease => 10 % stands => 100,000*0.1 bacetria. After two hours 90% decrease => 10% stands => 100,000*0.1^2. After three hours, they stand 100,000 * 0.1^3. After four hours, 100,000*0.1^4 and after five hours 100,000*0.1^5 = 1 bacteria. Answer: 1 bacteria. If the inital count is different you just have to muliply the inicial count time (0.1^n) to get the number of bacteria after n hours, and if the number of hours is 5, then the factor is (0.1^5). </span>

8 0

3 years ago

Read 2 more answers