The Sequence:
1 , 1+2 , 1+2+3 , 1+2+3+4, ...
here, every term is an AP. finding the general formula for the sum of the elements of each term is:
Sₙ =
<em> [where x = number of term, a = first term and d = common difference]</em>
here, the first term is always 1 and so is the common difference.
Sₙ = 
Sₙ =
= 
which is the formula for a general term in our series
now, we need to find the sum of the first n terms of this series
![\displaystyle\sum_{x=1}^{n} [\frac{1}{2}(x + x^{2})]](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csum_%7Bx%3D1%7D%5E%7Bn%7D%20%5B%5Cfrac%7B1%7D%7B2%7D%28x%20%2B%20x%5E%7B2%7D%29%5D)
![\displaystyle\frac{1}{2} [\sum_{x=1}^{n} (x) + \sum_{x=1}^{n}(x^{2})]](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac%7B1%7D%7B2%7D%20%5B%5Csum_%7Bx%3D1%7D%5E%7Bn%7D%20%28x%29%20%2B%20%5Csum_%7Bx%3D1%7D%5E%7Bn%7D%28x%5E%7B2%7D%29%5D)
in this formula, for the first term, it's just an AP from x = 1 to x = n
for the second term, we have a general formula 
![\frac{1}{2}[\frac{n}{2}(2a + (n-1)d)+ \frac{n(n+1)(2n+1)}{6} ]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B%5Cfrac%7Bn%7D%7B2%7D%282a%20%2B%20%28n-1%29d%29%2B%20%5Cfrac%7Bn%28n%2B1%29%282n%2B1%29%7D%7B6%7D%20%20%5D)
in this AP (first term), the first term and the common difference is 1 as well
![\frac{1}{2}[\frac{n}{2}(2 + n-1)+ \frac{n(n+1)(2n+1)}{6} ]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B%5Cfrac%7Bn%7D%7B2%7D%282%20%2B%20n-1%29%2B%20%5Cfrac%7Bn%28n%2B1%29%282n%2B1%29%7D%7B6%7D%20%20%5D)
![\frac{1}{2}[\frac{n}{2}(n+1)+ \frac{n(n+1)(2n+1)}{6} ]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B%5Cfrac%7Bn%7D%7B2%7D%28n%2B1%29%2B%20%5Cfrac%7Bn%28n%2B1%29%282n%2B1%29%7D%7B6%7D%20%20%5D)
![[\frac{n}{4}(n+1)+ \frac{n(n+1)(2n+1)}{12} ]](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bn%7D%7B4%7D%28n%2B1%29%2B%20%5Cfrac%7Bn%28n%2B1%29%282n%2B1%29%7D%7B12%7D%20%20%5D)
![\frac{n}{4}(n+1) [1+\frac{(2n+1)}{3} ]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B4%7D%28n%2B1%29%20%5B1%2B%5Cfrac%7B%282n%2B1%29%7D%7B3%7D%20%5D)
![\frac{n}{4}(n+1) [\frac{(3+2n+1)}{3} ]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B4%7D%28n%2B1%29%20%5B%5Cfrac%7B%283%2B2n%2B1%29%7D%7B3%7D%20%5D)
![\frac{n}{4}(n+1) [\frac{(2n+4)}{3} ]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B4%7D%28n%2B1%29%20%5B%5Cfrac%7B%282n%2B4%29%7D%7B3%7D%20%5D)
![\frac{n}{2}(n+1) [\frac{(n+2)}{3} ]](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B2%7D%28n%2B1%29%20%5B%5Cfrac%7B%28n%2B2%29%7D%7B3%7D%20%5D)

which is the sum of n terms of the given sequence
Answer:
x=8
Step-by-step explanation:
x+7=15
-7 -7
x=8
Mark me Brainliest?
Answer:
Could you please check if you've written the question properly
This question doesn't provide enough information
<h2>
Please mark as brainliest for further answers :)</h2>
Answer:49.... yep
Step-by-step explanation: 49,,,
Answer:

Step-by-step explanation:
given data;
B = 16m
b =8 m
height H = 4 m
length L = 32 m
volume of any right cylinder = (Area of bottom) \times (length)
Volume = A* L
The area of a trapezoid is



therefore volume is given as
volume = 48*32
