Answer:
Number of year to get $10,000 as interest = 7.5 year (Approx)
Step-by-step explanation:
Given:
Initial investment = $20,000
Interest on investment = $10,000
Rate of interest = 5.6% = 0.056
Find:
Number of year to get $10,000 as interest:
Computation:
![Interest\ on\ investment = Initial\ investment[(1+r)^n-1]\\\\10,000 = 20,000[(1+0.056)-1]\\\\0.5=(1.056)^n-1\\\\1.5 =(1.056)^n\\\\n=7.44](https://tex.z-dn.net/?f=Interest%5C%20on%5C%20investment%20%3D%20Initial%5C%20investment%5B%281%2Br%29%5En-1%5D%5C%5C%5C%5C10%2C000%20%3D%2020%2C000%5B%281%2B0.056%29-1%5D%5C%5C%5C%5C0.5%3D%281.056%29%5En-1%5C%5C%5C%5C1.5%20%3D%281.056%29%5En%5C%5C%5C%5Cn%3D7.44)
Number of year to get $10,000 as interest = 7.44
Number of year to get $10,000 as interest = 7.5 year (Approx)
Answer: 24.52%
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Work Shown:
Convert the time 7:45, which represents 7 min 45 sec, to seconds only
7:45 = (7 min) + (45 sec)
7:45 = (7*60 sec) + (45 sec)
7:45 = (420 sec) + (45 sec)
7:45 = (420+45) sec
7:45 = 465 sec
Do the same for 5:51
5:51 = (5 min) + (51 sec)
5:51 = (5*60 sec) + (51 sec)
5:51 = (300 sec) + (51 sec)
5:51 = (300+51) sec
5:51 = 351 sec
So the initial time is 465 seconds and it drops to 351 seconds
Subtract the values to find the amount dropped: 465-351 = 114
Divide that difference over the initial time: 114/465 = 0.24516
Move the decimal over 2 spots to the right to convert to a percentage: 0.24516 --> 24.516%
Then round to the nearest hundredth of a percent (2 decimal places) to go from 24.516% to 24.52% which is our final answer
So the reduction is roughly 24.52%
This means if you took 24.52% of the initial time and subtracted it off, then you'd get to about 351 seconds.
Option C would be the correct answer :)
Answer:
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Step-by-step explanation:
AJ is writing a report about Calvin Coolidge. He's including information about the former president's early days. Should he quote directly from a biography of Coolidge or paraphrase the information? Why?️
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