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3 years ago

Insomnia, headaches, and panic are all signs of: a. Test depression b. Test anxiety c. Test confusion

Advanced Placement (AP)

2 answers:

Vesna [10]3 years ago

8 0

Answer: Test anxiety

Explanation:

The anxiety can be defined as the body's natural response to the stress conditions. The fear of feeling apprehension or the feeling of fear.

There are some of the symptoms that shows anxiety. These symptoms are fear, lack of sleep, pain, Cold, sweaty, numb or tingling hands or feet.

These symptoms represents anxiety and test must be performed if there are such symptoms visible in a person.

Lubov Fominskaja [6]3 years ago

3 0

The answer to this question is B

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For time t≥0 , the acceleration of an object moving in a straight line is given by a(t)=sin(t23). what is the net change in velo

Firlakuza [10]

The net change in velocity during the given time interval is equal to -0.665.

<u>Given the following data:</u>

Initial time = 0.75 seconds.

Final time = 2.25 seconds.

Acceleration, $a(t) = sin(\frac{t^2}{3} )$

<h3>How to calculate the net change in velocity.</h3>

Since acceleration is the rate of change of velocity of an object, we would derive an expression for the velocity by differentiating with respect to time:

$V(t) = \frac{d}{dt} a(t)\\\\V(t) = \frac{d}{dt} (sin(\frac{t^2}{3} ))\\\\V(t) = cos( \frac{t^2}{3})(\frac{2t}{3})\\\\V(t) = \frac{2t}{3}cos( \frac{t^2}{3})$

Substituting the time interval, we have:

$V(t) = \frac{2\times 2.25}{3}cos( \frac{2.25^2}{3})- \frac{2\times 0.75}{3}cos( \frac{0.75^2}{3})\\\\V(t) = \frac{4.5}{3}cos( \frac{5.0625}{3})- \frac{1.5}{3}cos( \frac{0.5625}{3})\\\\V(t) =1.5(-0.11643)-0.5(0.98247)$

V(t) = -0.665.

Read more on acceleration here: brainly.com/question/24728358

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