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Mnenie [13.5K]
2 years ago
12

5

Mathematics
1 answer:
LekaFEV [45]2 years ago
8 0

Answer: y-1=\dfrac32(x+3)

Step-by-step explanation:

Slope of a line passes through (a,b) and (c,d) = \dfrac{d-b}{c-a}

In graph(below) given line is passing through (-2,-4) and (2,2) .

Slope of the given line passing through (-2,-4) and (2,2) =\dfrac{-4-2}{-2-2}=\dfrac{-6}{-4}=\dfrac{3}{2}

Since parallel lines have equal slope . That means slope of the required line would be .

Equation of a line passing through (a,b) and has slope m is given by :_

(y-b)=m(x-a)

Then, Equation of a line passing through(-3, 1) and has slope =  is given by

(y-1)=\dfrac32(x-(-3))\\\\\Rightarrow\ y-1=\dfrac32(x+3)

Required equation: y-1=\dfrac32(x+3)

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