Question

5

Answer 1

Answer: $y-1=\dfrac32(x+3)$

Step-by-step explanation:

Slope of a line passes through (a,b) and (c,d) = $\dfrac{d-b}{c-a}$

In graph(below) given line is passing through (-2,-4) and (2,2) .

Slope of the given line passing through (-2,-4) and (2,2) =$\dfrac{-4-2}{-2-2}=\dfrac{-6}{-4}=\dfrac{3}{2}$

Since parallel lines have equal slope . That means slope of the required line would be .

Equation of a line passing through (a,b) and has slope m is given by :_

(y-b)=m(x-a)

Then, Equation of a line passing through(-3, 1) and has slope =  is given by

$(y-1)=\dfrac32(x-(-3))\\\\\Rightarrow\ y-1=\dfrac32(x+3)$

Required equation: $y-1=\dfrac32(x+3)$