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omeli [17]
3 years ago
10

What are the constant terms in the expression? 8m−5n+2+m−14

Mathematics
2 answers:
Maslowich3 years ago
6 0

Answer: 2 , -14

Step-by-step explanation:

We know that the constant terms are the specific terms in an algebraic expression that have only numbers or numerical value or without any variable.  

For example : The constant term in 4x^2 -5m+16  is 16.

Let's take one more example , the constant term in 3x-2y-4-7xy is -4.

Given expression is : 8m-5n+2+m-14

Here, the terms are : 8m,\ -5n,\ 2,\ m,\ -14

Terms having variable = 8m,\ -5n,\ m

Terms without variable = 2 , -14

⇒ Constant terms =2 , -14

Hence, the constant terms in the given expression = 2 , -14

elena-s [515]3 years ago
5 0
The constant terms are: -14, and +2
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Answer:

6 groups

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Step-by-step explanation:

To find the answer, first find the Greatest Common Factor or the GCF. The GCF in this case is 6. So, the amount of groups is 6. Then divide each number by 6, so there will be 2 girls in each group and 3 boys in each group.

8 0
3 years ago
Which statement describes the lines whose equations are y=1/3x+12 and 6y=2x+6
ICE Princess25 [194]
First, you should solve both equations for the same variable. Since the first one is already solved for y, solve the second equation for y as well.

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y = \frac{1}{3}x + 1

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4 0
3 years ago
If you could please help me that would be great.
Brut [27]
No.1
r=9

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No.5
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8 0
1 year ago
When n=343 college students are randomly selected and surveyed, it is found that x=110 own a car. Find a 99% confidence interval
Liono4ka [1.6K]

Answer:

The margin of error will be "0.65". A further explanation is provided below.

Step-by-step explanation:

The given values are:

n = 343

x = 110

At 99% confidence level,

\alpha = 1-99%

  =1-0.99

  =0.01

then,

\frac{\alpha}{2} =\frac{0.01}{2}

  =0.005

or,

Z_{\frac{\alpha}{2} }=Z_{0.005}

     =2.576

Now,

The point estimate will be:

⇒  \hat{P}=\frac{x}{n}

⇒      =\frac{110}{343}

⇒      =0.321

or,

⇒  1-\hat{P}=1-0.321

⇒            =0.679

The margin of error will be:

⇒  E=Z_{\frac{\alpha}{2} }\times \sqrt (\frac{(\hat{P}\times (1 - \hat{P})) }{n} )

On substituting the above values, we get

⇒      =2.576\times \sqrt{\frac{0.321\times 0.679}{343} }

⇒      =2.576\times \sqrt{\frac{0.217959}{343} }

⇒      =0.065

hence,

⇒  \hat{P}-E

⇒  0.321-0.065

⇒  0.256,0.386

6 0
3 years ago
I need help with this
emmasim [6.3K]

Answer:

31.4

Step-by-step explanation:

2x3.14x5=31.4

(2x3.14xRadius)

Please Give Me Brainliest lol

7 0
3 years ago
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