Can you find the area of C and F?

Find the zeros of the following polynomial functions, with their multiplicities. (a) f(x)= (x +1)(x − 1)(x² +1) (b) g(x) = (x −

larisa [96]

Answer:

a) zeros of the function are x = 1 and, x = -1

b) zeros of the function are x = 2 and, x = 4

c) zeros of the function are x = $\frac{3}{2}$

d) zeros of the function are x = $\frac{-4}{3}$ and, x = 17

Step-by-step explanation:

Zeros of the function are the values of the variable that will lead to the result of the equation being zero.

Thus,

a) f(x)= (x +1)(x − 1)(x² +1)

now,

for the (x +1)(x − 1)(x² +1) = 0

the condition that must be followed is

(x +1) = 0 ..........(1)

or

(x − 1) = 0 ..........(2)

or

(x² +1) = 0 ...........(3)

considering the equation 1, we have

(x +1) = 0

or

x = -1

for

(x − 1) = 0

x = 1

and,

for (x² +1) = 0

or

x² = -1

or

x = √(-1) (neglected as it is a imaginary root)

Thus,

zeros of the function are x = 1 and, x = -1

b) g(x) = (x − 4)³(x − 2)⁸

now,

for the (x − 4)³(x − 2)⁸ = 0

the condition that must be followed is

(x − 4)³ = 0 ..........(1)

or

(x − 2)⁸ = 0 ..........(2)

considering the equation 1, we have

(x − 4)³ = 0

or

x -4 = 0

or

x = 4

and,

for (x − 2)⁸ = 0

or

x - 2 = 0

or

x = 2

Thus,

zeros of the function are x = 2 and, x = 4

c) h(x) = (2x − 3)⁵

now,

for the (2x − 3)⁵ = 0

the condition that must be followed is

(2x − 3)⁵ = 0

or

2x - 3 = 0

or

2x = 3

or

x = $\frac{3}{2}$

Thus,

zeros of the function are x = $\frac{3}{2}$

d) k(x) =(3x +4)¹⁰⁰(x − 17)⁴

now,

for the (3x +4)¹⁰⁰(x − 17)⁴ = 0

the condition that must be followed is

(3x +4)¹⁰⁰ = 0 ..........(1)

or

(x − 17)⁴ = 0 ..........(2)

considering the equation 1, we have

(3x +4)¹⁰⁰ = 0

or

(3x +4) = 0

or

3x = -4

or

x = $\frac{-4}{3}$

and,

for (x − 17)⁴ = 0

or

x - 17 = 0

or

x = 17

Thus,

zeros of the function are x = $\frac{-4}{3}$ and, x = 17

7 0

3 years ago

20 POINTS + BRAINLY Complete the table.

Elanso [62]

The frequency of the data set that matches with the interval stated are:

50 - 54: 2

55 - 59: 6

60 - 64: 7

65 - 69: 3

70 - 74: 2

<h3>What is a Frequency?</h3>

Frequency is the number of times a data point or a set of points within an interval appears often in a data set.

The corresponding frequency to each of the interval given for the data would be as follows:

50 - 54: 2

55 - 59: 6

60 - 64: 7

65 - 69: 3

70 - 74: 2

Learn more about the frequency of a data on:

brainly.com/question/15422753

#SPJ1

3 0

2 years ago

Solve for x. Round your answer to the nearest tenth.

valkas [14]

Answer:

1. x = 11.5

2. x = 14.35

Step-by-step explanation:

$1. \: sin(angleBAC) = \frac{BC}{AB}$

$sin(35°) = \frac{x}{20}$

x = 11.472 ≈ 11.5

$2. \: tan(angleBAC) = \frac{BC}{AB}$

$tan(64°) = \frac{x}{7}$

x = 14.352 ≈ 14.35

HOPE THIS HELPS AND HAVE A NICE DAY <3

5 0

2 years ago

Prove or disprove the figure defined by points A, B, C, d is a rhombus

just olya [345]

Answer:

It is not a rhombus, because all the internal angles are equal.

Step-by-step explanation:

A rhombus is a figure that has four sides of equal length, and 2 internal angles that are smaller than the other two internal angles.

First, let's look at figure ABCD.

We can see that all the sides have equal length by just counting the number of squares that each side takes (each side is 12 units long)

So now we need to see the angles.

Remember that if two lines are perpendicular, then the angle formed by those two lines is exactly 90°.

We can see that the segment BC is horizontal (the y-value of B is the same than the y-value of C)

While the segment CD is vertical (the x-value of C is the same than the x-vale of D)

Then one segment is horizontal, and the other is vertical, which means that the segments are perpendicular, thus the angle C is 90°.

Now we can do the same for segments CD and DA

We already know that CD is a vertical segment.

For segment DA we can see that the y-value of D is the same as the y-value of A, then this segment is horizontal, this means that segments CD and DA are perpendiculars, which means that D = 90°.

Because DA is parallel to BC, and CD is parallel to BA, we can conclude that:

A = 90°

B = 90°

Then all the angles are equal, so this is not a rhombus. (it is a square)

4 0

3 years ago

Which graphs have domains that contain all real numbers ?

seropon [69]

Answer:

Graphs 1, 2, 3

Step-by-step explanation:

Graph 1 represents a linear function with a domain containing all real numbers, as any input substituted into the equation or function will produce a corresponding output. The arrows on the opposite ends of the line represents the infinite input values that have its corresponding output values.

Graph 2 represents a quadratic function with a domain containing all real numbers, as it does not have any constraints in terms of input values. As it opens up, the graph of the parabola infinitely widens (horizontally).

Graph 3 represents an absolute value function with a domain containing all real numbers. Similar to the explanation for graph 2 on quadratic functions, the downward-facing graph of the given absolute value function widens infinitely horizontally, as it does not have any constraints on input values.

6 0

3 years ago