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Nezavi [6.7K]
3 years ago
7

Find the exact real value of arccos(-sqrt(2)/2).

Mathematics
1 answer:
sineoko [7]3 years ago
5 0
 arccos(-sqrt(2)/2). range of <span>cos − 1 ( x )=<span>[ 0 , π ]
</span></span>= arccos(0.706 )
=45 degrees
hope  this helps
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