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Nezavi [6.7K]
3 years ago
7

Find the exact real value of arccos(-sqrt(2)/2).

Mathematics
1 answer:
sineoko [7]3 years ago
5 0
 arccos(-sqrt(2)/2). range of <span>cos − 1 ( x )=<span>[ 0 , π ]
</span></span>= arccos(0.706 )
=45 degrees
hope  this helps
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What is the value of the expression below?
timurjin [86]

Answer:

I don't see a correct answer.  See below.

Step-by-step explanation:

Thanks for clarifying the question.  But if 27√3 is the correct expression, I don't see an answer option that fits.  

√3 = 1.732

27*(1.732) = 46.77

But all the answer options are whole numbers.  The presence of√3 makes it difficult to find an expression that would result in a whole number.  Expressions such as:

27/√9 = 9, or

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I hope this helps.

3 0
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What is the range of this function
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Step-by-step explanation:

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7 0
3 years ago
What equation do I need to use?
goldenfox [79]
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Answer:

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Read 2 more answers
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