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2 years ago

What is the value of the expression below?

Mathematics

1 answer:

timurjin [86]2 years ago

3 0

Answer:

I don't see a correct answer. See below.

Step-by-step explanation:

Thanks for clarifying the question. But if 27√3 is the correct expression, I don't see an answer option that fits.

√3 = 1.732

27*(1.732) = 46.77

But all the answer options are whole numbers. The presence of√3 makes it difficult to find an expression that would result in a whole number. Expressions such as:

27/√9 = 9, or

√27/√3 = 3

would be more consistent with producing a whole number result.

I hope this helps.

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Find all zeros of the polynomial P(x) = x3 − 2x2 − 3x + 10. Express any non-real roots in the form a + bi.

Strike441 [17]

Answer:

$x = - 2 \: or \: x = 2 - i \: or \: x = 2 + i$

Step-by-step explanation:

The given equation is

$p(x) = {x}^{3} - 2 {x}^{2} - 3x + 10$

We can see that:

$p( - 2) = {( - 2)}^{3} - 2 {( -2) }^{2} - 3( - 2)+ 10$

$p( - 2) = - 8- 8 + 6+ 10 = 0$

This means x=-2 is a zero of p(x).

From the long division in the attachment,

We can rewrite the polynomial as:

${x}^{3} - 2 {x}^{2} - 3x + 10 = (x + 2)( {x}^{2} - 4x + 5)$

We now find solution to the quadratic part:

${x}^{2} - 4x + 5 = 0$

This is given by:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a}$

We plug in the values to get:

$x = \frac{ - - 4 \pm \sqrt{ {( - 4)}^{2} - 4 \times 1 \times 5} }{2 \times 1}$

$x = \frac{ 4 \pm \sqrt{ 16 - 20} }{2 }$

$x = \frac{ 4 \pm \sqrt{ - 4} }{2 }$

$x = \frac{ 4 \pm2i}{2 } \\ x = 2 \pm \: i \\ x = 2 - i \: or \: x = 2 + i$

Therefore all solutions are:

$x = - 2 \: or \: x = 2 - i \: or \: x = 2 + i$

4 0

4 years ago

There are 365 days in a year. There are four seasons in a year (winter, spring, summer, fall). Each season has the same number o

Vinvika [58]

Answer:

I think it is 272

Step-by-step explanation:

Not every month has the same amount Winter is about 89 days long. -- Autumn is 90 days. -- Spring is 93 days

8 0

3 years ago

Read 2 more answers

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Cerrena [4.2K]

Answer:

-4

Step-by-step explanation:

4 0

3 years ago

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In an optical ﬁbre, the power drops by a factor of 10 approximately every 30 km. If the transmit power is 0. 35 W, how far will

IgorC [24]

Answer:

30000 km

Step-by-step explanation:

First convert the transmit power into μW, considering 1 W = 1000000 μW:

0.35 W = 0.35*1000000 μW = 350000 μW

Find how many factors of 10 the power dropped:

350000 / 350 = 1000

Find the distance:

1000*30 km = 30000 km

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3 years ago

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I am Lyosha [343]

4.5 I'm pretty sure I hope I was right and hope this helps

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4 years ago