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tekilochka [14]
3 years ago
11

Question 11 the length of a rectangle is six times its width. if the perimeter of the rectangle is 98 m , find its area.

Mathematics
1 answer:
andrezito [222]3 years ago
4 0
Let's look at the formula to solve the perimeter.
2l+2w=98
We know that l=6w
Let's put that into the equation.
2(6w)+2w=98
12w+2w=98
14w=98
98÷14=7
So the width is 7. Let's find the length.
Since the length is six times the width: 7×6= 42
So, the length is 42 while the width is 7. We need to find the area.
42×7=294
The area is 294 m².
Tell me if this helps!!
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jeka94

The Law of Cosines features the 3 side lengths of a triangle, plus the measure of the angle opposite one of those sides.


We want angle x, which is opposite the side of length 39.


Then: a^2 = b^2 - 2ab cos C becomes 39^2 = 36^2 + 59^2 - 2(36)(59)cos x


or 1521 = 3481 + 1296 - 2(36)(59) cos x


Subtract (3481+1296) from both sides: 1521 - 4777 = -4248cos x

-3256 = -4248cos x

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Then: cosx = --------------- = 0.766

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Solving for x: x = arccos -0.766 = 0.698 radian, or 40 degrees (answer)

5 0
3 years ago
1/2(8x-6) = x + 9 solve ... hurry
QveST [7]

Answer:

x=4

Step-by-step explanation:

4x-3=x+9

4x-x-3=9

4x-x=9+3

3x=9+3

3x=12

3/3

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5 0
3 years ago
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Someone h e l p me on this it is geometry
ladessa [460]

BC = 6 km

<u>/</u><u> </u> ACB = 34°

AC = ?

cos 34° = \frac{BC}{AC}

=> 0.829 = \frac{6}{AC}

=> AC = \frac{6}{0.829}

=> AC = 7.23763570567

=> AC = 7 km

=> AC = 10 km\:\:\:\:\:\:\:\: (nearest tenth)

\\

<h3>Answer : 10 km</h3>

\\\\\\\\

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7 0
3 years ago
Write the general polynomial p(x) if its only zeros are 1 4 and -3 with multiplicites 3 2 and 1 respectively what is the degree
kompoz [17]

Answer:

The 6th degree polynomial is p(x) = (x-1)^3(x-4)^2(x+3)

Step-by-step explanation:

Zeros of a function:

Given a polynomial f(x), this polynomial has roots x_{1}, x_{2}, x_{n} such that it can be written as: a(x - x_{1})*(x - x_{2})*...*(x-x_n), in which a is the leading coefficient.

Zero 1 with multiplicity 3.

So

p(x) = (x-1)^3

Zero 4 with multiplicity 2.

Considering also the zero 1 with multiplicity 3.

p(x) = (x-1)^3(x-4)^2

Zero -3 with multiplicity 1:

Considering the previous zeros:

p(x) = (x-1)^3(x-4)^2(x-(-3)) = (x-1)^3(x-4)^2(x+3)

Degree is the multiplication of the multiplicities of the zeros. So

3*2*1 = 6

The 6th degree polynomial is p(x) = (x-1)^3(x-4)^2(x+3)

8 0
3 years ago
If someone can help me with this question please?
Katyanochek1 [597]

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Explanation:

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1. We are given that RE = 2AR and RT = 2GR.

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It is nice, though maybe not absolutely essential, to write the segment names in order of corresponding vertices.

4. Having shown that two sides are proportional and the angle between them is congruent, we can claim similarity using the SAS Theorem.

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