The Law of Cosines features the 3 side lengths of a triangle, plus the measure of the angle opposite one of those sides.
We want angle x, which is opposite the side of length 39.
Then: a^2 = b^2 - 2ab cos C becomes 39^2 = 36^2 + 59^2 - 2(36)(59)cos x
or 1521 = 3481 + 1296 - 2(36)(59) cos x
Subtract (3481+1296) from both sides: 1521 - 4777 = -4248cos x
-3256 = -4248cos x
-3256
Then: cosx = --------------- = 0.766
-4248
Solving for x: x = arccos -0.766 = 0.698 radian, or 40 degrees (answer)
Answer:
x=4
Step-by-step explanation:
4x-3=x+9
4x-x-3=9
4x-x=9+3
3x=9+3
3x=12
3/3
12/3=4
x=4
BC = 6 km
<u>/</u><u> </u> ACB = 34°
AC = ?
cos 34° = 
=> 0.829 = 
=> AC = 
=> AC = 7.23763570567
=> AC = 7 km
=> AC = 10 km
(nearest tenth)

<h3>Answer : 10 km</h3>

HOPE IT HELPS
PLEASE MARK ME BRAINLIEST ☺️
Answer:
The 6th degree polynomial is 
Step-by-step explanation:
Zeros of a function:
Given a polynomial f(x), this polynomial has roots
such that it can be written as:
, in which a is the leading coefficient.
Zero 1 with multiplicity 3.
So

Zero 4 with multiplicity 2.
Considering also the zero 1 with multiplicity 3.

Zero -3 with multiplicity 1:
Considering the previous zeros:

Degree is the multiplication of the multiplicities of the zeros. So
3*2*1 = 6
The 6th degree polynomial is 
9514 1404 393
Explanation:
The three Reasons tell you what to look for to put in the Statement blank.
1. We are given that RE = 2AR and RT = 2GR.
2. The only vertical angles in the figure are ...
∠GRA ≅ ∠TRE
3. Using the given relation between the sides, we can write the proportion ...
RE/RA = RT/RG = 2
It is nice, though maybe not absolutely essential, to write the segment names in order of corresponding vertices.
4. Having shown that two sides are proportional and the angle between them is congruent, we can claim similarity using the SAS Theorem.