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Ber [7]
3 years ago
9

What is the range of the function y = -x2 + 1?

Mathematics
1 answer:
meriva3 years ago
3 0
<span><span>y = 2 + 2sec(2x) The upper part of the range will be when the secant has the smallest positive value up to infinity. The smallest positive value of the secant is 1 So the minimum of the upper part of the range of y = 2 + 2sec(2x) is 2 + 2(1) = 2 + 2 = 4 So the upper part of the range is [4, ) The lower part of the range will be from negative infinity up to when the secant has the largest negative value. The largest negative value of the secant is -1 So the maximum of the lower part of the range of y = 2 + 2sec(2x) is 2 + 2(-1) = 2 - 2 = 0 So the lower part of the range is (, 0]. Therefore the range is (, 0] U [4, ) </span>
</span>
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The first one:

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One of the two equations required in the system of equations needed to determine the dollar amount of phone and computer sales Houa made is y = x + 600.

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Let x represents the dollar amount of phone sales Houa made, and y represents the dollar amount of computer sales she made.

Therefore, a system of equations that could be used to determine x and y can be written as follows:

y = x + 600 ........................................................... (1)

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7 0
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Kobotan [32]
We have an triangle:
base=4 in
height=3 in,
This triangle can be dividided into two equal triangles, we need calculate the hypotenuse.
leg₁=4 in/2=2 in
leg₂=3 in

Pythagoras law:
hypotenuse²=leg₁²+leg₂²
hypotenuse²=(2 in)²+(3 in)²
hypotenuse²=4 in²+9 in²
hypotenuse²=13 in²
hypotenuse=√13 in.

Now, we can find the surface area.
Surface area=2 *(rectangle area)+base area + 2(triangle area)
rectangle area=10 in x √13 in=10√13 in²
base area=10 in  x 4 in=40 in²
Triangle area=(4 in x 3 in)/2=6 in²

Surface area=2(10√13 in²)+40 in²+2(6 in²)=(20√13+52) in²≈124.11 in²

Answer: 124.11 in²
7 0
3 years ago
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