What is the range of the function y = -x2 + 1?

1 answer:

meriva3 years ago

3 0

y = 2 + 2sec(2x) The upper part of the range will be when the secant has the smallest positive value up to infinity. The smallest positive value of the secant is 1 So the minimum of the upper part of the range of y = 2 + 2sec(2x) is 2 + 2(1) = 2 + 2 = 4 So the upper part of the range is [4, ) The lower part of the range will be from negative infinity up to when the secant has the largest negative value. The largest negative value of the secant is -1 So the maximum of the lower part of the range of y = 2 + 2sec(2x) is 2 + 2(-1) = 2 - 2 = 0 So the lower part of the range is (, 0]. Therefore the range is (, 0] U [4, )

You might be interested in

Tom works part-time at a theme park. Last week he worked the following hours but he needs to complete his timesheet in decimals.

alex41 [277]

A= 7.25 B= 6.75 C= 5.2 D= 6.1

8 0

3 years ago

Read 2 more answers

A die is rolled. What is the probability that the number is a factor of 6 or more than 2? Does this scenario represent mutually

goblinko [34]

Factors of 6 are : 1,2,3 and 6.

Let us find probability of getting the number that is a factor of 6.

$P(\text{ The number is a factor of 6})=\frac{4}{6} =\frac{2}{3}$

Now let us find probability of getting a number more than 2 (3,4,5,6).

$P(\text{ The number is a greater than 2})=\frac{4}{6} =\frac{2}{3}$

We can see that these two events are mutually inclusive events. We can find probability of mutually inclusive events by formula $P(\text{X or Y})=P(X)+P(Y)-P(\text{X and Y})$ .