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Ber [7]
3 years ago
9

What is the range of the function y = -x2 + 1?

Mathematics
1 answer:
meriva3 years ago
3 0
<span><span>y = 2 + 2sec(2x) The upper part of the range will be when the secant has the smallest positive value up to infinity. The smallest positive value of the secant is 1 So the minimum of the upper part of the range of y = 2 + 2sec(2x) is 2 + 2(1) = 2 + 2 = 4 So the upper part of the range is [4, ) The lower part of the range will be from negative infinity up to when the secant has the largest negative value. The largest negative value of the secant is -1 So the maximum of the lower part of the range of y = 2 + 2sec(2x) is 2 + 2(-1) = 2 - 2 = 0 So the lower part of the range is (, 0]. Therefore the range is (, 0] U [4, ) </span>
</span>
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Juan brought 4 Tshirts and leather jacket. The T shirts were all the same price, and the price of the leather jacket was 6 times
Alex

Let us say that:

x = the number of T shirts bought = 4

y = the number of leather jackets bought = 1

a = the price of the T shirts

b = the price of the leather jackets

 

With the given variables, we can say that the total cost is:

total cost = a x + b y

 

Since, b = 6 a, therefore:

total cost = a x + 6 a y

total cost = a (x + 6 y)

 

Since total cost is 209, therefore we can calculate for a since x and y are also given:

209 = a (4 + 6 * 1)

209 = a (10)

a = $20.9

 

<span>Therefore each T shirt cost $20.9</span>

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Hope this helps.

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