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Ber [7]
3 years ago
9

What is the range of the function y = -x2 + 1?

Mathematics
1 answer:
meriva3 years ago
3 0
<span><span>y = 2 + 2sec(2x) The upper part of the range will be when the secant has the smallest positive value up to infinity. The smallest positive value of the secant is 1 So the minimum of the upper part of the range of y = 2 + 2sec(2x) is 2 + 2(1) = 2 + 2 = 4 So the upper part of the range is [4, ) The lower part of the range will be from negative infinity up to when the secant has the largest negative value. The largest negative value of the secant is -1 So the maximum of the lower part of the range of y = 2 + 2sec(2x) is 2 + 2(-1) = 2 - 2 = 0 So the lower part of the range is (, 0]. Therefore the range is (, 0] U [4, ) </span>
</span>
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A complex number z=a+bi had an absolute value of 3.28. What could the values of a and b be ? A.a=1.5,b=1.7 C.a=1.7,b=2.8
Levart [38]
The given complex number is ⇒ z = a + b i
The absolute value of z = √( a² + b² ) = 3.28
So, we will check which of the options will give 3.28

<span>( A) IF ⇒⇒ a=1.5 and b=1.7
</span>
<span>∴ √( a² + b² ) = √( 1.5² + 1.7²) = √5.14 ≈ 2.27
</span>
===================================

<span>(B) IF ⇒⇒ a=1.5 and b=3.3
</span>
<span>∴ √( a² + b² ) = √(1.5² + 3.3²) = √13.14 ≈ 3.62
</span>
====================================

<span>(C) IF ⇒⇒ a=1.7 and b=2.8
</span>
<span>∴ √( a² + b² ) = √(1.7² + 2.8²) = √10.73 ≈ 3.28
</span>
====================================

<span>(D) IF ⇒⇒ a=2.8 and b=3.3
</span>
∴ √( a² + b² ) = √(2.8² + 3.3²) = √18.73 ≈ 4.33
=====================================
So, the correct answer is option (C) <span>a=1.7,b=2.8</span>
4 0
3 years ago
DG¯¯¯¯¯¯ , EG¯¯¯¯¯ , and FG¯¯¯¯¯ are perpendicular bisectors of the sides of △ABC . DG=5 cm and BD=12 cm.
jonny [76]
Given that <span>DG, EG, and FG are perpendicular bisectors of the sides of △ABC, this means that the point of intersection, G, is the circumcenter of the triangle and hence A</span><span>G, BG, and CG are equal.

Given that </span><span>DG = 5 cm and BD = 12 cm, then

BG= \sqrt{DG^2+BD^2}  \\  \\ = \sqrt{5^2+12^2} = \sqrt{25+144}  \\  \\ = \sqrt{169} =13

Since AG = BG = CG, therefore, CG = 13 cm.</span>
3 0
3 years ago
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Korvikt [17]

C is your correct answer

6 0
3 years ago
How do I solve 3(x+5)=39
azamat
3(x+5)=39

3 * x + 3 * 5 = 39

3x + 15 = 39

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4 0
3 years ago
Read 2 more answers
Please help I’m struggling so bad
Anastaziya [24]

Answer:

a) (100,70)

b) the point of intersection means that Auto-Loans and Rent-a-Car companies will both have a daily cost of $70 when the distance driven is 100km.

c) Auto-Loans: y = 1/2x+20

Rent-a-Car: y = 1/5x+50

d) this means that the third company would have a y-intercept of 0 (its daily cost and distance would start at 0) and it would also have a daily cost of $70 when the distance driven is 100km. this would also mean that the third company's line would have a slope of 7/10

Third company's line: y=7/10x+0

(I'm sorry if I got anything wrong, but I hope this helps!)

Step-by-step explanation:

a) the point of intersection is where the two lines meet

this is at (100, 70)

b) in the context of this problem, the point of intersection means that Auto-Loans and Rent-a-Car companies will both have a daily cost of $70 when the distance driven is 100km.

c) Auto-Loans: y = 1/2x+20

Rent-a-Car: y = 1/5x+50

*this is because the slope of a line can be found by rise/run, and the y-intercept can be found by where it is located on the y-axis, since x would be 0.)

(for example, for Auto-Loans, the slope would be rise/run which in this case would be 10/20 or 1/2. the y-intercept is 20 since the y is 20 when it is on the y-axis).

d) if a third company's line starts at (0,0) and has the same point of intersection, this means that the third company would have a y-intercept of 0 (its daily cost and distance would start at 0) and it would also have a daily cost of $70 when the distance driven is 100km. this would also mean that the third company's line would have a slope of 7/10

Third company's line: y=7/10x+0

3 0
2 years ago
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