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3 years ago

Construct a 3 by 3 nonzero matrix A such that the vector 1,1,1 is a solution to Ax=b

1 answer:

marta [7]3 years ago

8 0

What does your vector b has to be?

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IrinaVladis [17]

$- 2(x + 3) = - 2(x + 1) - 4 \\ - 2x - 6 = - 2x - 2 - 4 \\ - 2x = - 2x \\ x = x$

Every x is a solution.

5 0

3 years ago

vivado [14]

i don’t know for sure but i just figured it out....

7 0

3 years ago

ycow [4]

The coordinates of the endpoints of the midsegment for △LMN that is parallel to LN are (3, 4.5) and (3, 3).

Explanation:

Given that △LMN

We need to determine the coordinates of the endpoints of the midsegment for △LMN that is parallel to LN

The midsegment of the triangle parallel to side LN is the midsegment connecting the midpoint of side LM and the midpoint of side MN.

The midpoint of LM is given by

$\left(\frac{0+6}{2}, \frac{5+4}{2}\right)$

Simplifying, we get,

$(\frac{3}{2}, \frac{9}{2} )=(3,4.5)$

The midpoint of MN is given by

$\left(\frac{0+6}{2}, \frac{2+1}{2}\right)=(3,3)$

Thus, the coordinates of the endpoints of the midsegment for △LMN that is parallel to LN are (3, 4.5) and (3, 3).

4 0

3 years ago

puteri [66]

Answer: 24

Step-by-step explanation:

Take the factorial of that number.

4! = 4*3*2*1=24

8 0

4 years ago

sasho [114]

I hope this helps you 132-x+6x-12=180 5x=60 x=12 6y+18+132-x=180 6y+150-12=180 6y=42 y=7

6 0

3 years ago