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sergey [27]
3 years ago
13

Consider the system of equations y= -2 + 4, 3y+x=-3 which statement is true of the system of equations

Mathematics
1 answer:
WINSTONCH [101]3 years ago
4 0
3x-4y+2 hahahaha its not me pep perillp ie eewewr its jwghvjbe rijwte ru
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Ramon has applied to MBA programs at both Harvard and Stanford. He thinks the probability that Harvard will admit him is 0.5, th
ivolga24 [154]

Answer:

(a) The Venn diagram is attached below.

(b) The probability that neither university admits Ramon is 0.20.

(c) The probability that Ramon gets into Stanford but not Harvard 0.30.

Step-by-step explanation:

Let's denote the events as follows:

<em>H</em> = Ramon gets admitted to Harvard

<em>S</em> = Ramon gets admitted to Stanford.

The information provided is:

P (H) = 0.50

P (S) = 0.50

P (H ∩ S) = 0.20

(a)

The Venn diagram is attached below.

(b)

Compute the probability that Ramon gets admitted in neither Harvard nor Stanford as follows:

P(H^{c}\cup S^{c})=1-P(H\cup S) \\= 1 - [P(H)+P(S)-P(H\cap S)]\\=1-[0.50+0.50-0.20]\\=1-0.80\\=0.20

Thus, the probability that neither university admits Ramon is 0.20.

(c)

Compute the probability that Ramon gets admitted in Stanford but not in Harvard as follows:

P(H^{c}\cup S)=P(S)-P(H\cap S) \\= 0.50-0.20\\=0.30

Thus, the probability that Ramon gets into Stanford but not Harvard 0.30.

7 0
3 years ago
Find the distance of (-7,-5) and (-3,4) round to the nearest tenth​
Luba_88 [7]

Answer:

7.2 units

Step-by-step explanation:

Distance² = (Change in y)² + (Change in x)²

Distance² = (4 - -5)² + (-3 - -7)²

Distance² = 36 + 16

Distance² = 52

Distance = 7.211102551

Rounding off the answer to nearest tenth gives 7.2 units

7 0
3 years ago
Simplify to create an equivalent expression6(7-3y)+6(y+1)
RideAnS [48]

Answer:

48-12y

Step-by-step explanation:

6(7-3y) + 6(y+1)

distribute the 6 on both parentheses

42-18y+6y+6

combine like terms

42-12y+6

combine like terms again

48-12y

5 0
3 years ago
Find MO and PR <br> ............................................................
ddd [48]

MO = 12 and PR = 3

Solution:

Given \triangle M N O \sim \Delta P Q R.

Perimeter of ΔMNO = 48

Perimeter of ΔPQR = 12

MO = 12x and PR = x + 2

<em>If two triangles are similar, then the ratio of corresponding sides is equal to the ratio of perimeter of the triangles.</em>

$\Rightarrow \frac{\text{Perimeter of }\triangle MNO}{\text{Perimeter of }\triangle PQR} =\frac{MO}{PR}

$\Rightarrow \frac{48}{12} =\frac{12x}{x+2}

Do cross multiplication.

$\Rightarrow 48({x+2})= 12(12x)

$\Rightarrow 48x+96= 144x

Subtract 48x from both sides.

$\Rightarrow 48x+96-48x= 144x-48x

$\Rightarrow 96= 96x

Divide by 96 on both sides, we get

⇒ 1 = x

⇒ x = 1

Substitute x = 1 in MO an PR.

MO = 12(1) = 12

PR = 1 + 2 = 3

Therefore MO = 12 and PR = 3.

7 0
3 years ago
So what the is the answer
Tasya [4]
The answer to life, the universe and everything is 42.
8 0
3 years ago
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