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ira [324]
3 years ago
8

Suppose you went to a carnival. the price in was $6, and you paid $0.50 to get on each ride. if you went to the carnival and rod

eo 11 rides, how much did you spend?
Mathematics
1 answer:
DochEvi [55]3 years ago
8 0
.5(11)+6= $11.50 Multiply the price of each ride by how many rides you went on and add the price of the carnival ticket itself.
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lions [1.4K]
The answer for this is B
5 0
3 years ago
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Yellow Taxi Cabs charges a $7 flat rate in addition to $2.25 per mile. Kate has $100 to spend on transportation. How many miles
enyata [817]
Kate can travel 41.33 miles without exceeding her limit. This problem can be solved by using y = 2.25x  + 7 linear equation with the "y" variable as the total cost that Kate must pay after she has traveled with the cab and the "x" variable as Kate's traveling distance. The equation has 7 for its constant value which is the $7 flat rate. We will find 41.33 miles as the traveling distance if we substituted the total cost with 100, which is the maximum amount that can be paid by Kate for the traveling purpose.
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3 years ago
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Katena32 [7]
The answer is B) multiply 3 by 3. With that 2 on top, that doesn't mean 3 times 2, that means multiply 3 by itself, however many times the number says, if that makes sense. So if there's a 2 above the 3, then that would be 3*3. If it was a 5 instead of a two, that would mean 3*3*3*3*3. Not 3*5.
3 0
3 years ago
Veronica bought 20 bags of candy for a school dance. The first 5 bags cost $1.79 each. The rest of the bags cost $1.19 each. How
scZoUnD [109]

Answer:

$26.80

Step-by-step explanation:

multiply 1.79 by 5 and you get 8.95

multiply 1.19 by 15 now because there are 15 uncounted bags left and you get 17.85

add together and you get 26.8. she spent 26.8 dollars on candy

4 0
2 years ago
If f(x)=ln(sin(2x)), f''(π/4) is equal to​
Licemer1 [7]

Use the chain rule to compute the second derivative:

f(x)=\ln(\sin(2x))

The first derivative is

f'(x)=(\ln(\sin(2x)))'=\dfrac{(\sin(2x))'}{\sin(2x)}=\dfrac{\cos(2x)(2x)'}{\sin(2x)}=\dfrac{2\cos(2x)}{\sin(2x)}

f'(x)=2\cot(2x)

Then the second derivative is

f''(x)=(2\cot(2x))'=-2\csc^2(2x)(2x)'

f''(x)=-4\csc^2(2x)

Then plug in π/4 for <em>x</em> :

f''\left(\dfrac\pi4\right)=-4\csc^2\left(\dfrac{2\pi}4\right)=-4

4 0
3 years ago
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