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frosja888 [35]
3 years ago
6

What is the error in this problem

Mathematics
1 answer:
dlinn [17]3 years ago
4 0

Answer:

10). m∠x = 47°

11). x = 30.96

Step-by-step explanation:

10). By applying Sine rule in the given triangle DEF,

   \frac{\text{SinF}}{\text{DE}}=\frac{\text{SinD}}{\text{EF}}

   \frac{\text{Sinx}}{7}=\frac{\text{Sin110}}{9}

   Sin(x) = \frac{7\times (\text{Sin110})}{9}

   Sin(x) = 0.7309

   m∠x = \text{Sin}^{-1}(0.7309)

   m∠x = 46.96°

   m∠x ≈ 47°

11). By applying Sine rule in ΔRST,

   \frac{\text{SinR}}{\text{ST}}=\frac{\text{SinT}}{\text{RS}}

   \frac{\text{Sin120}}{35}=\frac{\text{Sin50}}{x}

   x = \frac{35\times (\text{Sin50})}{\text{Sin120}}

   x = 30.96   

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[ZA WARUDO] stops time and throws 200 knives at Jotaro Kujo. Then he adds one more and summons a ROAD ROLLER DA And smashes jota
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Answer:

169 knives

Step-by-step explanation:

What we know:

ZW threw 200 knives at Jotaro, then adds one more. This makes 201 knives, initially.

However, the RRD subtracts 32 from 201, making it 169 knives that ZW threw.

201 - 30 - 2 = 171 - 2 = 169 knives

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Step-by-step explanation:

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Is 2/3 equivalent to 1/3 if it isn't then which is bigger plz help and will give a thanks
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PLEASE HELP ME!!
ASHA 777 [7]

The first three standard deviation for coSport include;

  • 1 standard deviation above and below the mean = 6.9 and 6.1
  • 2 standard deviation above and below the mean = 7.3 and 5.7
  • 3 standard deviation above and below the mean = 7.7 and 5.3

The first three standard deviation for Blockbuster include;

  • 1 standard deviation above and below the mean = 5.2 and 4.0
  • 2 standard deviation above and below the mean = 5.8 and 3.4
  • 3 standard deviation above and below the mean = 6.4 and 2.8

"<em>Check the image I added for the plot of the normal distribution</em>"

<u />

<u>In the given chart;</u>

sample size of the coSport, = 400

the mean of the coSport, M = 6.5

standard deviation of the coSport, d = 0.4

The first standard deviation above and below the mean for coSport is calculated as;

at 34% of the sample size = 0.34 x 400 = 136

above the mean = M + d = 6.5 + 0.4 = 6.9

below the mean = M - d = 6.5 - 0.4 = 6.1

The second standard deviation above and below the mean for coSport is calculated as;

at 14% of the sample size = 0.14 x 400 = 56

above the mean = M + 2d = 6.5 + 2(0.4) = 7.3

below the mean = M - 2d = 6.5 - 2(0.4) = 5.7

The third standard deviation above and below the mean for coSport is calculated as;

at 2% of the sample size = 0.02 x 400 = 8

above the mean = M + 3d = 6.5 + 3(0.4) = 7.7

below the mean = M - 3d = 6.5 - 3(0.4) = 5.3

<u>Also In the given chart;</u>

  • sample size of the Blockbuster, = 600
  • the mean of the Blockbuster, M = 4.6
  • standard deviation of the Blockbuster, d = 0.6

The first standard deviation above and below the mean for Blockbuster is calculated as;

at 34% of the sample size = 0.34 x 600 = 204

above the mean = M + d = 4.6 + 0.6 = 5.2

below the mean = M - d = 4.6 - 0.6 = 4

The second standard deviation above and below the mean for Blockbuster is calculated as;

at 14% of the sample size = 0.14 x 600 = 84

above the mean = M + 2d = 4.6 + 2(0.6) = 5.8

below the mean = M - 2d = 4.6 - 2(0.6) = 3.4

The third standard deviation above and below the mean for Blockbuster is calculated as;

at 2% of the sample size = 0.02 x 600 = 12

above the mean = M + 3d = 4.6 + 3(0.6) = 6.4

below the mean = M - 3d = 4.6 - 2(0.6) = 2.8

Learn more here: brainly.com/question/23418254

3 0
3 years ago
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