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frosja888 [35]
3 years ago
6

What is the error in this problem

Mathematics
1 answer:
dlinn [17]3 years ago
4 0

Answer:

10). m∠x = 47°

11). x = 30.96

Step-by-step explanation:

10). By applying Sine rule in the given triangle DEF,

   \frac{\text{SinF}}{\text{DE}}=\frac{\text{SinD}}{\text{EF}}

   \frac{\text{Sinx}}{7}=\frac{\text{Sin110}}{9}

   Sin(x) = \frac{7\times (\text{Sin110})}{9}

   Sin(x) = 0.7309

   m∠x = \text{Sin}^{-1}(0.7309)

   m∠x = 46.96°

   m∠x ≈ 47°

11). By applying Sine rule in ΔRST,

   \frac{\text{SinR}}{\text{ST}}=\frac{\text{SinT}}{\text{RS}}

   \frac{\text{Sin120}}{35}=\frac{\text{Sin50}}{x}

   x = \frac{35\times (\text{Sin50})}{\text{Sin120}}

   x = 30.96   

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The numbers of regular season wins for 10 football teams in a given season are given below. Determine the range, mean, variance,
galina1969 [7]

Answer:

Range = 13

Mean = 8.3

Variance = 17.61

Step-by-step explanation:

Given the population dataset :

2, 9, 15, 4, 12, 9, 13, 6, 3, 10

1.) Range : (maximum - minimum)

Maximum = 15 ; minimum = 2

Range = (15 - 2) = 13

2.) population mean (μ) :

μ = ΣX / n

n = sample size

μ = (2 + 9 + 15 + 4 + 12 + 9 + 13 + 6 + 3 + 10) / 10

μ = 83 / 10

μ = 8.3

3.) Population variance (s²)

Σ(x - μ)² / n

=[(2 - 8.3)^2 + (9 - 8.3)^2 + (15 - 8.3)^2 + (4 - 8.3)^2 + (12 - 8.3)^2 + (9 - 8.3)^2 + (13 - 8.3)^2 + (6 - 8.3)^2 + (3 - 8.3)^2 + (10 - 8.3)^2] / 10

s² = 176.1 / 10

s² = 17.61

8 0
3 years ago
FIND THE SUM OF 20 TERMS OF THE ARITHMETIC SERIES IN WHICH 3rd TERM IS 7 AND 7th TERM IS 2 MORE THAN THREE TIMES ITS 3rd TERM
algol13

Answer:

740

Step-by-step explanation:

The n th term of an arithmetic series is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₃ = 7 and a₇ = (3 × 7) + 2 = 21 + 2 = 23 , then

a₁ + 2d = 7 → (1)

a₁ + 6d = 23 → (2)

Subtract (1) from (2) term by term

4d = 16 ( divide both sides by 4 )

d = 4

Substitute d = 4 into (1)

a₁ + 2(4) = 7

a₁ + 8 = 7 ( subtract 8 from both sides )

a₁ = - 1

The sum to n terms of an arithmetic series is

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ] , thus

S_{20} = \frac{20}{2} [ (2 × - 1) + (19 × 4) ]

     = 10(- 2 + 76) = 10 × 74 = 740

8 0
3 years ago
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