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pychu [463]
3 years ago
13

The most common Native American language used in 2010 is Navajo, with about 169,000 people speaking the language nationally. If

there are about 308.7 million people in the United States, what fraction of people speak Navajo? Write the ratio of these two population numbers as a decimal and percent.
Mathematics
2 answers:
Diano4ka-milaya [45]3 years ago
4 0
169,000/308,700,000 which can be simplified to 169/308,700 and decimal form just divide 169,000 by 308,700,000 and you get .0005474571, and percentage multiply the decimal by 100 so you get .055% (rounded)
ASHA 777 [7]3 years ago
3 0

Answer:

The fraction of people who speaks Navajo in USA is 0.000547 that is equal to  0.0547% of global population.

Step-by-step explanation:

Calculate the number of people who speak Navajo per inhabitant living in the United States like this:

169000 navajo speakers / 308700000 inhabitants in the united states

The above is equal to the reason 169:308700, that is, 169 people speak Navajo in the United States for every 308700 inhabitants, a division that is also the same as saying that 0.000547 people speak Navajo for every inhabitant living in the United States.

To convert the previous quotient into a percentage, it must be multiplied by 100. In this way 0.000547x100 , it is equal to 0.0547%, a value that represents the percentage of inhabitants of the United States who speak Navajo.

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Solve the following system:<br> y=1<br> y=-6x-5
Mandarinka [93]

Answer:

x = -1

y = 1

Step-by-step explanation:

<u><em>Since it gives you "y", plug in the number given into the equation:</em></u>

y = -6x - 5

1 = -6x - 5

<u><em>Then, add 5 to both sides:</em></u>

1 = -6x - 5

+5       + 5

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6 = -6x

<em><u>Divide both sides by -6:</u></em>

6 = -6x

-1 = x

So now you have, x = -1 and y = 1

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3 years ago
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1. Draw an appropriate Venn diagram to depict each of the following sets. U = The set of integers. A = The set of even integers.
CaHeK987 [17]

The attached diagram represents the Venn diagram of the sets

<h3>How to draw the Venn diagram?</h3>

The sets are given as:

  • The universal set, U = The set of integers.
  • A = The set of even integers.
  • B = The set of odd integers.
  • C = The set of multiples of 3.
  • D= The set of prime numbers

From the above representation, we have the following highlights:

  • Set A and set B will not intersect, because no number can be even and odd
  • Set C and set D will intersect set A because they have common elements 6 and 2, respectively
  • Set C and set D will intersect set B because they have common elements 3 and 3, respectively

Using the above highlights, we can now draw the Venn diagram

See attachment for the Venn diagram

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3 0
2 years ago
What is 927 divided by 9
aliya0001 [1]

Answer:103

Step-by-step explanation:

6 0
3 years ago
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A farmer sells eggs in containers holding a dozen eggs. If he has 2178 eggs, how many containers will be filled completely? How
BARSIC [14]

Answer:

~181 containers filled completely, 6 eggs left over

Step-by-step explanation:

2178 ÷ 12 (a dozen, the number of eggs per container) = 181.5 containers

181 × 12 = 2,172 eggs

2,178 eggs - 2,172 = 6 eggs left over

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3 years ago
Discuss the continuity of the function on the closed interval.Function Intervalf(x) = 9 − x, x ≤ 09 + 12x, x &gt; 0 [−4, 5]The f
quester [9]

Answer:

It is continuous since \lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)

Step-by-step explanation:

We are given that the function is defined as follows f(x) = 9-x, x\leq 0 and f(x) = 9+12x, x>0 and we want to check the continuity in the interval [-4,5]. Note that this a piecewise function whose only critical point (that might be a candidate of a discontinuity)  x=0 since at this point is where the function "changes" of definition. Note that 9-x and 9+12x are polynomials that are continous over all \mathbb{R}. So F is continous in the intervals [-4,0) and (0,5]. To check if f(x) is continuous at 0, we must check that

\lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x) (this is the definition of continuity at x=0)

Note that if x=0, then f(x) = 9-x. So, f(0)=9. On the same time, note that

\lim_{x\to 0^{-}} f(x) = \lim_{x\to 0^{-}} 9-x = 9. This result is because the function 9-x is continous at x=0, so the left-hand limit is equal to the value of the function at 0.

Note that when x>0, we have that f(x) = 9+12x. In this case, we have that

\lim_{x\to 0^{+}} f(x) = \lim_{x\to 0^{+}} 9+12x = 9. As before, this result is because the function 9+12x is continous at x=0, so the right-hand limit is equal to the value of the function at 0.

Thus, \lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)=9, so by definition, f is continuous at x=0, hence continuous over the interval [-4,5].

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3 years ago
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