Question

The population of a town in 2000 was 430. The population is increasing at a rate of 0.9% every year. What will be the projected population of the town in 2010? Round your answer to the nearest whole number.
a 470
b 500
c 503
d 289

Answer 1

Answer: a 470

Step-by-step explanation:

The exponential growth equation with rate of growth r in time period t is given by :-

$y=A(1+r)^t$, where A is the initial amount

Given : The rate of growth of population every year : 0.9% =0.009

The initial population = 430

Then , the exponential growth equation in time period t is given by :-

$y=430(1+0.009)^t$

In 2010 or for t= 10 years

The projected population of the town will be :-

$y=430(1.009)^{10}=470.305565305\approx470$

Hence, the projected population of the town in 2010 is about 470.