The following table shows Jace's earnings based on the number of hours that he works.

Write the if/else statement as the conditional expression that performs the same option result = x < y ? x * 5 : a b;

Semenov [28]

The conditional statement is

if x < y:

result = x * 5

<h3>How to write the if/else statement as the conditional expression that performs the same option?</h3>

The statement is given as:

result = x < y ? x * 5

The above means that,

the variable result is assigned x * 5 if x < y

So, the conditional statement is

if x < y:

result = x * 5

Read more about conditional statement at

brainly.com/question/11073037

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8 0

2 years ago

Suppose that a standardized biology exam has a mean score of 80% correct, with a standard deviation of 3. The school administrat

NemiM [27]

Answer:

The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

A sample of 65 students from the freshmen class is used and a mean score of 76% correct is obtained.

This means that $n = 65, \pi = 0.76$

99% confidence level

So $\alpha = 0.005$ , z is the value of Z that has a pvalue of $1 - \frac{0.005}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.76 - 2.575\sqrt{\frac{0.76*0.24}{65}} = 0.6236$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.76 + 2.575\sqrt{\frac{0.76*0.24}{65}} = 0.8964$

0.6236*100 = 62.36%

0.8964*100 = 89.64%

The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).

6 0

3 years ago

What is the answer pls answer 13 points !!!!!!!!!!!!!!!

Yuliya22 [10]

Answer:

The first one

Step-by-step explanation:

304,913

6 0

3 years ago

Read 2 more answers

A president, treasurer, and secretary, all di erent, are to be chosen from a club consisting of 12 people (whose names are I, J,

Ierofanga [76]

Answer:

There are 220 choices

Step-by-step explanation:

Given

$People = 12$

$Selection =3$ (President, Treasurer and Secretary)

Required

Determine number of selection (if no restriction)

This is calculated using the following combination formula:

$^nC_r = \frac{n!}{(n - r)!r!}$

Where

$n = 12$

$r= 3$

So, we have:

$^nC_r = \frac{n!}{(n - r)!r!}$

$^{12}C_3 = \frac{12!}{(12 - 3)!3!}$

$^{12}C_3 = \frac{12!}{9!3!}$

$^{12}C_3 = \frac{12*11*10*9!}{9!3!}$

$^{12}C_3 = \frac{12*11*10}{3!}$

$^{12}C_3 = \frac{12*11*10}{3*2*1}$

$^{12}C_3 = \frac{12*11*10}{6}$

$^{12}C_3 = 2*11*10$

$^{12}C_3 = 220\ ways$

<em>There are 220 choices</em>

8 0

3 years ago

A past study claims that adults in America spend an average of 17 hours a week on leisure activities. A researcher wanted to tes

8090 [49]

Answer:

The claim is false.

Step-by-step explanation:

Given the data :

13 24 21 37 15 25 18 22 40 32

The sample mean and standard deviation can ben calculated for the given sample.

Using calculator :

Sample mean, xbar = 24.7

Sample standard deviation, s = 9.04

Sample size, n = 10

The hypothesis :

H0 : μ = 17

H1 : μ ≠ 17

The test statistic :

(xbar - μ) ÷ (s/√(n))

(24.7 - 17) ÷ (9.04/√(10))

7.7 / 2.8586990

Test statistic = 2.694

We can obtain the Pvalue, at α = 0.05 ; df = n-1 = 9

Pvalue = 0.0246

Since Pvalue < α ; we reject the null ; Hence, there is significant evidence to conclude that an adult American does not spend average of 17 hours in leisure

5 0

3 years ago