The conditional statement is
if x < y:
result = x * 5
<h3>How to write the if/else statement as the conditional expression that performs the same option?</h3>
The statement is given as:
result = x < y ? x * 5
The above means that,
the variable result is assigned x * 5 if x < y
So, the conditional statement is
if x < y:
result = x * 5
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Answer:
The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
A sample of 65 students from the freshmen class is used and a mean score of 76% correct is obtained.
This means that 
99% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

0.6236*100 = 62.36%
0.8964*100 = 89.64%
The 99% confidence interval is between 62.36%(lower bound) and 89.64%(upper bound).
Answer:
The first one
Step-by-step explanation:
304,913
Answer:
There are 220 choices
Step-by-step explanation:
Given

(President, Treasurer and Secretary)
Required
Determine number of selection (if no restriction)
This is calculated using the following combination formula:

Where


So, we have:









<em>There are 220 choices</em>
Answer:
The claim is false.
Step-by-step explanation:
Given the data :
13 24 21 37 15 25 18 22 40 32
The sample mean and standard deviation can ben calculated for the given sample.
Using calculator :
Sample mean, xbar = 24.7
Sample standard deviation, s = 9.04
Sample size, n = 10
The hypothesis :
H0 : μ = 17
H1 : μ ≠ 17
The test statistic :
(xbar - μ) ÷ (s/√(n))
(24.7 - 17) ÷ (9.04/√(10))
7.7 / 2.8586990
Test statistic = 2.694
We can obtain the Pvalue, at α = 0.05 ; df = n-1 = 9
Pvalue = 0.0246
Since Pvalue < α ; we reject the null ; Hence, there is significant evidence to conclude that an adult American does not spend average of 17 hours in leisure