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vlada-n [284]
2 years ago
15

The following table shows Jace's earnings based on the number of hours that he works.

Mathematics
1 answer:
statuscvo [17]2 years ago
7 0

Answer:

no

Step-by-step explanation:

because no

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Need help with this pls help
drek231 [11]

Answer:

$3425

Step-by-step explanation:

5% of $68500 is $3425

5 0
2 years ago
Read 2 more answers
What is the lateral area of the rectangular prism?
weeeeeb [17]
Area of rectangle prism, to find the answer, use this formula: 2 x ( h x d + h x w + d x w )

So it would look like this: 2 x ( 12 x 6 + 12 x 7 + 6 x 7 ) = 396

I would say the answer is B. 396 in2


Hope I helped ; )
4 0
3 years ago
(09.02)
Ivenika [448]

Answer:

4th option

Step-by-step explanation:

x² - 2x - 3 = 0 ( add 3 to both sides )

x² - 2x = 3

using the method of completing the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 1)x + 1 = 3 + 1

(x - 1)² = 4

4 0
2 years ago
The population of a community is known to increase at a rate proportional to the number of people present at time t. The initial
qaws [65]

Answer:

Step-by-step explanation:

Let P be the population of the community

So the population of a community increase at a rate proportional to the number of people present at a time

That is

\frac{dp}{dt} \propto p\\\\\frac{dp}{dt} =kp\\\\ [k \texttt {is constant}]\\\\\frac{dp}{dt} -kp =0

Solve this equation we get

p(t)=p_0e^{kt}---(1)

where p is the present population

p₀ is the initial population

If the  initial population as doubled in 5 years

that is time t = 5 years

We get

2p_o=p_oe^{5k}\\\\e^{5k}=2

Apply In on both side to get

Ine^{5k}=In2\\\\5k=In2\\\\k=\frac{In2}{5} \\\\\therefore k=\frac{In2}{5}

Substitute k=\frac{In2}{5}  in p(t)=p_oe^{kt} to get

\large \boxed {p(t)=p_oe^{\frac{In2}{5}t }}

Given that population of a community is 9000 at 3 years

substitute t = 3 in {p(t)=p_oe^{\frac{In2}{5}t }}

p(3)=p_oe^{3 (\frac{In2}{5}) }\\\\9000=p_oe^{3 (\frac{In2}{5}) }\\\\p_o=\frac{9000}{e^{3(\frac{In2}{5} )}} \\\\=5937.8

<h3>Therefore, the initial population is 5937.8</h3>
7 0
3 years ago
Which expression is equivalent to (b^n)^m<br> A. b^n/m<br> B. b^n-m<br> C. b^n•m<br> D. b^n+m
sattari [20]
The answer is c because it is multiplying
3 0
3 years ago
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