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3 years ago

What is the result of converting 1500 yards into miles?

Mathematics

2 answers:

Anastasy [175]3 years ago

8 0

Answer:

0.8522727 miles

Step-by-step explanation:

MrRissso [65]3 years ago

8 0

Answer:

0.8522727 miles

Step-by-step explanation:

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Suppose you believe that Florio Company's stock price is going to decline from its current level of $82.50 sometime during the n

Anastasy [175]

Answer:

B. $19.90

Step-by-step explanation:

The put option will be exercised only if the final price is below the strike price. If the final price exceeds the strike price, there will simply be a loss equal to the cost of the option.

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4 years ago

I need the quotient to 4 / 100 12

Lady bird [3.3K]

2503 is the answer, you can use a calculator to find this by simply plugging it in or use the long division method

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3 years ago

A baseball player hit 57 home runs in a season. Of the 57 home runs, 15 went to right field, 20 went to right center field, 1

Sidana [21]

Place the part (amount going to the left field), over the total amount of homerun:

(a) 2/57 is your probability

(b) Divide 2/57

2/57 = 0.035, or 3.5%

YES, it is unusual for this player to hit a home run to left field, for he only has a 3.5% chance.

hope this helps

8 0

3 years ago

USA Today reports that about 25% of all prison parolees become repeat offenders. Alice is a social worker whose job is to counse

pychu [463]

Answer:

a) $P(X=0)=(4C0)(0.75)^0 (1-0.75)^{4-0}=0.0039$

$P(X=1)=(4C1)(0.75)^1 (1-0.75)^{4-1}=0.0469$

$P(X=2)=(4C2)(0.75)^2 (1-0.75)^{4-2}=0.211$

$P(X=3)=(4C3)(0.75)^2 (1-0.75)^{4-3}=0.422$

$P(X=4)=(4C4)(0.75)^2 (1-0.75)^{4-4}=0.316$

b) $E(X) = np = 4*0.75=3$

c) $Sd(X) =\sqrt{np(1-p)}=\sqrt{4*0.75*(1-0.75)}=0.866$

d) $P(X \geq 3) \geq 0.98$

And the dsitribution that satisfy this is $X\sim Binom(n=9,p=0.75$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=4, p=1-0.25=0.75)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Part a

$P(X=0)=(4C0)(0.75)^0 (1-0.75)^{4-0}=0.0039$

$P(X=1)=(4C1)(0.75)^1 (1-0.75)^{4-1}=0.0469$

$P(X=2)=(4C2)(0.75)^2 (1-0.75)^{4-2}=0.211$

$P(X=3)=(4C3)(0.75)^2 (1-0.75)^{4-3}=0.422$

$P(X=4)=(4C4)(0.75)^2 (1-0.75)^{4-4}=0.316$

Part b

The expected value is givn by:

$E(X) = np = 4*0.75=3$

Part c

For the standard deviation we have this:

$Sd(X) =\sqrt{np(1-p)}=\sqrt{4*0.75*(1-0.75)}=0.866$

Part d

For this case the sample size needs to be higher or equal to 9. Since we need a value such that:

$P(X \geq 3) \geq 0.98$

And the dsitribution that satisfy this is $X\sim Binom(n=9,p=0.75$

We can verify this using the following code:

"=1-BINOM.DIST(3,9,0.75,TRUE)" and we got 0.99 and the condition is satisfied.

4 0

3 years ago

I have a question. I'm doing a project and want to see how many people would like dogs or cats please comment your answer and if

FinnZ [79.3K]

I like both, but i have cats

8 0

4 years ago

Read 2 more answers