This shows that about 7 and 3 pounds of each chocolate were included in the mixture.
Let the number of pounds of both chocolates be x and y.
If Enrico sold a 10-pound box of assorted chocolates, hence;
x + y = 10 ................. 1
If some of the chocolates in the box sold for $1.75 per pound and some sold for $2.00 per pound with mixture sold for $1.90 per pound, then:
1.75x + 2x = 1.90 ................ 2
Solve equations 1 and 2 simultaneously.
x + y = 10 ................. 1 * 20
17.5x + 20x = 19 ................ 2 * 1
____________________________
20x + 20y = 200
17.5x + 20x = 19
Subtract
20x - 17.5x = 200 - 19
2.5x = 181x = 7.24
Substitute 7.24 into 1
x + y = 10
y = 10 - 7.24
x = 2.76
This shows that about 7 and 3 pounds of each chocolate were included in the mixture.
Learn more here: brainly.com/question/15165519
Answer:
Step-by-step explanation:
z(lower) = (15-15)/4 = 0
z(upper) = (19-15)/4= 1
z at 0 = .5
z at 1 = 0.841344746
(look these up in a Z table)
probability "between" = 0.841344746 - .5 = 0.3841344746
Answer: 5/2
Explanation:
According to 30-60-90 triangle rule:
The side opposite of 30 degree is equal to half of the hypotenuse and the hypotenuse here is 5 so therefore x = 5/2
x= | 1 < x < 3
x + 2 < 5 and x - 7 > -6
x < 5 - 2 and x > -6 + 7
I don't know if I am 100% right.
Your answer is C I’m sure about that!
