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Lesechka [4]
3 years ago
10

This is for my quiz) Wich table is linear and why is it linear?

Mathematics
1 answer:
Anestetic [448]3 years ago
8 0
Both graphs A and B are linear. In both graphs, the y value is going up at a constant rate in comparison to their x values. For example, in graph A every time the x value is increased by 1 the y value is increased by 2 values showing that they have the same gradient. For a graph to be linear it must have a constant rate of increase or decrease.
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3. Consider the figure below, What is the sum of m
sveticcg [70]

Answer:

you do not have enough information to determine

4 0
3 years ago
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Can anyone help me plzzz??!
Roman55 [17]

Answer:

X=1

Step-by-step explanation:

It’s 2 secant lines on a circle.

https://www.mathplanet.com/education/geometry/circles/advanced-information-about-circles

Look at that website. The part says that (ab*ad)=(ac*ae)

Doing that, we get

9*(9+11x)=10(10+8x)

81+99x=100+80x

19x=19

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4 0
3 years ago
Which equation represents the graphed function?<br><br> Submit
OverLord2011 [107]

3/2x - 3 = y

using y = mx + b, where m is slope and b is the y intercept, we can eliminate the top two answers by finding the y intercept at -3.

You can find the slope of the graph by using any given point and then calculating rise over run. In this case, the rise is 1.5, and the run is 1, which equates to 3/2

b = -3

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3 0
2 years ago
HELP PLS<br> Raise 5 to the 9th power, then subtract j from the result
jek_recluse [69]

Answer:

expression is (5^{9}) - j

Step-by-step explanation:

^^

5 is raised to the 9th power and then subtraced by j

you dont *really* need the () bc of pemdas but whatever

6 0
3 years ago
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Circle L is shown. Line segments K L and M L are radii. The length of K L is 12. Angle M L K is 60 degrees. Sector M L K with a
sergejj [24]

Answer:

120\pi square units

Step-by-step explanation:

We are given that

Radius of circle=12 units

Angle MLK=60 degree

We have to find the area of sector that is not shaded.

Area of shaded sector MLK=\frac{\theta}{360}\times \pi r^2

Area of shaded sector MLK=\frac{60}{360}\times \pi(12)^2=24 square units

Area of whole circle=\pi r^2=\pi (12)^2=144\pisquare units

Area of sector that is not shaded =Area of whole circle-Area of shaded sector MLK=144\pi-24\pi

Area of sector that is not shaded=120\pi square units

4 0
3 years ago
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