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2 years ago

How long will it take for a $3000 savings account to double its value at a simple interest rate of 10%?

1 answer:

7 0

Given P=$3000
R=10%
And double of P means A=$6000
Now , we know that
A = P×R×t÷100
6000=3000×10×t÷100
6000×100÷30000 =t
20=t
The Answer is 20 Yrs if rate was for year

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Drawing a card- four cards are drawn from a desk without replacement.Find these probabilities.

svetlana [45]

The deck consists of 4 jacks, 26 black cards, and 13 hearts.

There is only 1 way of drawing all 4 jacks: $\dbinom44=\dfrac{4!}{4!(4-4)!}=1$ .

There are $\dbinom{26}4=14,950$ ways of drawing 4 black cards.

There are $\dbinom{13}4=715$ ways of drawing 4 hearts.

There are $\dbinom{52}4=270,725$ ways of drawing any 4 cards.

The probabilities are then

$\dfrac{\binom44}{\binom{52}4}=\dfrac1{207,725}\approx0.00000369$

$\dfrac{\binom{26}4}{\binom{52}4}=\dfrac{46}{833}\approx0.0552$

$\dfrac{\binom{13}4}{\binom{52}4}=\dfrac{11}{4165}\approx0.00264$

5 0

2 years ago

A tree casts a shadow 27 m long. At the same time, the shadow cast by a 66-cm tall statue is 56 cm long. Find the height of the

Nata [24]

$\frac{height _{1} }{shadow_{1}} = \frac{height _{2} }{shadow_{2}}$

$\frac{height _{1} }{27m} = \frac{66cm}{56cm}$

$\frac{height _{1} }{2700cm} = \frac{66cm}{56cm}$

$2700*66=56*h _{1}$

$178200=56h _{1}$

$3182.1cm=h _{1}$

$\frac{3182.1cm}{1000cm} = 3.2m$

$height:3.2m$

6 0

2 years ago

Read 2 more answers

If p is true and q is false, then p ∨ q is true. <br> A. True<br> B. False

Marysya12 [62]

Answer:

no its false because p v q can only be true if both are true

Step-by-step explanation:

7 0

2 years ago

I need helpppp!!<br> Find the volume of the sphere. Round to the nearest tenth.<br> d = 9

weqwewe [10]

Answer: 381.7

Step by step explanation:

5 0

1 year ago

g Bonus: Assume that among the general pediatric population, 7 children out of every 1000 have DIPG (Diffuse Intrinsic Pontine G

patriot [66]

Answer:

0.9586

Step-by-step explanation:

From the information given:

7 children out of every 1000 children suffer from DIPG

A screening test designed contains 98% sensitivity & 84% specificity.

Now, from above:

The probability that the children have DIPG is:

$\mathbf{P(positive) = P(positive \ | \ DIPG) \times P(DIPG) + P(positive \ | \ not \DIPG)\times P(not \ DIPG)}$ $= 0.98\imes( \dfrac{7}{1000}) + (1-0.84) \times (1 - \dfrac{7}{1000})$

= (0.98 × 0.007) + 0.16( 1 - 0.007)

= 0.16574

So, the probability of not having DIPG now is:

$P(not \ DIPG \ | \ positive) = \dfrac{ P(positive \ | \ not DIPG)\timesP(not \ DIPG)} { P(positive)}$

$=\dfrac{ (1-0.84)\times (1 - \dfrac{7}{1000}) }{ 0.16574}$

$=\dfrac{ 0.16 ( 1 - 0.007) }{0.16574}$

= 0.9586

8 0

2 years ago