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netineya [11]
2 years ago
6

In △FEG , point H is between points E and F, point J is between points F and G, and HJ¯¯¯¯¯∥EG¯¯¯¯¯ .

Mathematics
1 answer:
CaHeK987 [17]2 years ago
5 0

Answer:

FJ=39\ units

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

If two triangles are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

In this problem

△FEG is similar with △FHJ -----> by AA Similarity Theorem

so

\frac{FE}{FH}=\frac{FG}{FJ}

we have

FE=HF+EH=26+14=40\ units

FH=HF=26\ units

FG=60\ units

substitute the given values

\frac{40}{26}=\frac{60}{FJ}

FJ=26(60)/40\\FJ=39\ units

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beks73 [17]
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8 0
3 years ago
You drive from your home to a vacation resort 420 miles away. You return on the same highway. The average velocity on the return
attashe74 [19]
<h2>Time required to complete the round​ trip T=\frac{420}{x}+\frac{420}{(x-15)} where x is average velocity on the outgoing​ trip.</h2>

Step-by-step explanation:

Let average velocity of outgoing trip = x mph

The average velocity on the return trip is 15 miles per hour slower than the average velocity on the outgoing trip.

Average velocity of return trip = (x-15) mph

Distance to vacation place = 420 miles

Distance to vacation place = Time for outgoing trip x average velocity of outgoing trip

          420=t_1\times x\\\\t_1=\frac{420}{x}

Distance to vacation place = Time for return trip x average velocity of return trip

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We have total time T = t₁ + t₂

That is

                     T=\frac{420}{x}+\frac{420}{(x-15)}

Time required to complete the round​ trip T=\frac{420}{x}+\frac{420}{(x-15)} where x is average velocity on the outgoing​ trip.

8 0
2 years ago
What is the justification for step 1
solniwko [45]

Answer:

what are you talking about??????

6 0
2 years ago
Change the following expression to an equivalent expression in exponential form
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Answer:

12^4/5

Step-by-step explanation:

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AysviL [449]

Answer:

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Really sorry if this is incorrect, I had this question on my Lesson 16 test, and I don't know if it's correct or not...

8 0
2 years ago
Read 2 more answers
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