12^3 = 1728; 14^3 = 2744;
Answer:
Molar mass = 254.60g/mol
Step-by-step explanation:
Mass = 8.02g
Volume = 812mL = 0.812L
Pressure (P) = 0.967atm
Temperature of the gas = 30°C = (30 + 273.15)K = 303.15K
Molecular weight = ?
To solve this question, we'll have to use ideal gas equation, PV = nRT
P = pressure of the gas
V = volume of the gas
n = number of moles of the gas
R = ideal gas constant = 0.082J/mol.K
T = temperature of the gas
PV = nRT
n = PV / RT
n = (0.967 * 0.812) / (0.082 * 303.15)
n = 0.7852 / 24.8583
n = 0.0315 moles
Number of moles = mass / molarmass
Molarmass = mass / number of moles
Molar mass = 8.02 / 0.0315
Molar mass = 254.60g/mol
The molar mass of the gas is 254.60g/mol
The answer would be 1/3 up 1 over 3.
Answer:
We use the power rule of exponents to find out that both sides of the equation equal 3^20 (or 3486784401).
Step-by-step explanation:
For this example, we can just use a calculator and find out that both (3^5)^4 and (3^4)^5 are the same value. But how do we know this algebraically?
When dealing with exponents, we must have a good understanding of the properties of exponents before doing any calculations.
For this example, I recognize that the power rule of exponents is being used:

So let's apply this rule to the given equation.
(3^5)^4 = (3^4)^5
3^(5*4) = 3^(4*5)
3^20 = 3^20
Now we know both sides of the equation equal 3^20 (or 3486784401).