Point C ∈

1 answer:

3 0

$\bf A\underset{\textit{1.5 times farther than CB}}{\stackrel{1.5x}{\rule[0.35em]{15em}{0.25pt}}}C\stackrel{x}{\rule[0.35em]{10em}{0.25pt}}B
\\\\\\
AB=AC+CB\implies \stackrel{AB}{30}=\stackrel{AC}{1.5x}+\stackrel{CB}{x}\implies 30=2.5x
\\\\\\
\cfrac{30}{2.5}=x\implies 12=x
\\\\[-0.35em]
~\dotfill\\\\
\stackrel{AC}{1.5(12)}\implies 18~\hspace{10em}\stackrel{CB}{12}$

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