Y= 1/2x + 8
i hope this helped
Answer:
![\large\boxed{(f-g)(x)=-x^2+3x+7}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%28f-g%29%28x%29%3D-x%5E2%2B3x%2B7%7D)
Step-by-step explanation:
![(f-g)(x)=f(x)-g(x)\\\\f(x)=3x+1,\ g(x)=x^2-6\\\\(f-g)(x)=(3x+1)-(x^2-6)=3x+1-x^2+6=-x^2+3x+7](https://tex.z-dn.net/?f=%28f-g%29%28x%29%3Df%28x%29-g%28x%29%5C%5C%5C%5Cf%28x%29%3D3x%2B1%2C%5C%20g%28x%29%3Dx%5E2-6%5C%5C%5C%5C%28f-g%29%28x%29%3D%283x%2B1%29-%28x%5E2-6%29%3D3x%2B1-x%5E2%2B6%3D-x%5E2%2B3x%2B7)
Answer with Step-by-step explanation:
We are given that a function f(x) is continuous on (
).
1.f'(-1)=0 and f''(-1)=-7
We have to find information about f.
When f'(-1)=0 and f''(-1)=-7 < 0
Then, function is maximum at x=-1.
Therefore, at x=-1, f has local maximum.
Answer:a)at x=-1 ,f has local maximum.
2.) if f'(4)=0 and f''(4)=0
We know that when f''(x)=0 then test fails then the function has not maximum or minimum.
Therefore, at x=4 , f has not a maximum or minimum.
Answer:c) at x=4, f has not a maximum or minimum.
Answer:
24
Step-by-step explanation:
8/ 1/3 =24