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Musya8 [376]
3 years ago
14

Can you help me with these 4 problems?

Mathematics
1 answer:
adoni [48]3 years ago
3 0
What are the questions attach a pic plz
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Triangle: solve for x
NARA [144]

Answer:

6 root two

Step-by-step explanation:

geometric mean for leg t.

24*3=x2

x2=72

x=root(72)

6 root two

if my answer helps please mark as brainliest.

6 0
3 years ago
Simplify expression X^2+x-2/x^3-x^2+2x-2
professor190 [17]

Answer:


=\frac {x+2}{x^2+2} is the simplest form of given expression.


Step-by-step explanation:

The given question is \frac{x^2+x-2}{x^3-x^2+2x-2}


To solve the problem we have to group or split middle term and then factorise


\frac{x^2+(2x-x)-2}{(x^3-x^2)+(2x-2)}


Taking x^2 common from first two terms of denominator and 2 from next two terms


= \frac{x^2+2x-x-2}{x^2(x-1)+2(x-1)}


Now,taking x common from first two terms of numerator and -1 from next two terms and in denominator taking(x-1) common from both terms


= \frac{ x(x+2)-1(x+2)}{(x-1)(x^2+2)}



=\frac{(x+2)(x-1)}{(x-1)(x^2+2)}


Now cancel out x-1 from both numerator and denominator we get


=\frac {x+2}{x^2+2} is the required simplest form.



7 0
3 years ago
after selling a dozen copies of the daily newspaper, a newsstand had fewer than 79 copies left. how many copies did the newsstan
Naya [18.7K]
90
-12. The newsstand had 90 copies at the beginning of the day
===
78
5 0
3 years ago
Because of three scarf is 26. 25. What is the unit price?
Dimas [21]
Each scarf costs $8.75.
5 0
3 years ago
2/3 divided by 11/15
NNADVOKAT [17]
You need to implement the process of "flip-flop" and multiply which is where you flip the second fraction and multiply.

\frac{2}{3}÷\frac{11}{15}⇒\frac{2}{3}×\frac{15}{11}

Now you multiply across. 2×15=30 and 3×11=33

So now it is \frac{30}{33}

-----------------------------------------------------------
To reduce to the lowest terms, find the GCF common factor

The GCF is 3

Divide both the numerator and denominator by 3

\frac{30}{33}÷\frac{3}{3}=\frac{10}{11}

Answer: \frac{10}{11}

7 0
3 years ago
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