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Blizzard [7]
3 years ago
11

Solve for K 3(k+5)=-2(3k-6)

Mathematics
1 answer:
Jet001 [13]3 years ago
5 0
3k+15=-6k+12. Combine like terms: 3=-3k. Isolate the k: 1=-k. Make k positive: -1=k, k=-1 :)
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Lim x->pi/3 ((2cosx-1)/(tan^2x-3))
beks73 [17]

You can check that the limit comes in an undefined form:

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In these cases, we can use de l'Hospital rule, and evaluate the limit of the ratio of the derivatives. We have:

\dfrac{\text{d}}{\text{d}x}2\cos(x)-1 = -2\sin(x)

and

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So, we have

\displaystyle \lim_{x\to\frac{\pi}{3}} \frac{2\cos(x)-1}{\tan^2(x)-3}=\lim_{x\to\frac{\pi}{3}} \dfrac{-2\sin(x)}{\frac{2\sin(x)}{\cos^3(x)}}=\lim_{x\to\frac{\pi}{3}}-\cos^3(x)=-\cos^3\left(\dfrac{\pi}{3}\right)

6 0
3 years ago
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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5 0
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