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SpyIntel [72]
3 years ago
7

Lim x->pi/3 ((2cosx-1)/(tan^2x-3))

Mathematics
1 answer:
beks73 [17]3 years ago
6 0

You can check that the limit comes in an undefined form:

\displaystyle \lim_{x\to\frac{\pi}{3}} \frac{2\cos(x)-1}{\tan^2(x)-3}=\dfrac{0}{0}

In these cases, we can use de l'Hospital rule, and evaluate the limit of the ratio of the derivatives. We have:

\dfrac{\text{d}}{\text{d}x}2\cos(x)-1 = -2\sin(x)

and

\dfrac{\text{d}}{\text{d}x}\tan^2(x)-3 = 2\dfrac{\tan(x)}{\cos^2(x)}=\dfrac{2\sin(x)}{\cos^3(x)}

So, we have

\displaystyle \lim_{x\to\frac{\pi}{3}} \frac{2\cos(x)-1}{\tan^2(x)-3}=\lim_{x\to\frac{\pi}{3}} \dfrac{-2\sin(x)}{\frac{2\sin(x)}{\cos^3(x)}}=\lim_{x\to\frac{\pi}{3}}-\cos^3(x)=-\cos^3\left(\dfrac{\pi}{3}\right)

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Please show ALL work!<br><br> Solve for x: log₂x+log₂(x-6)=4
Vlad [161]
Answer: x = 8

---------------------------------------------
---------------------------------------------

I'm going to use the notation log(2,x) to indicate "log base 2 of x". The first number is the base while the second is the expression inside the log (aka the argument of the log)

log(2,x) + log(2,(x-6)) = 4
log(2,x*(x-6)) = 4
x*(x-6) = 2^4
x*(x-6) = 16
x^2-6x = 16
x^2-6x-16 = 0
(x-8)(x+2) = 0
x-8 = 0 or x+2 = 0
x = 8 or x = -2

Recall that the domain of log(x) is x > 0. So x = -2 is not allowed. The same applies to log(2,x) as well.

Only x = 8 is a proper solution.

------------------------

You can use the change of base rule to check your work
log base 2 of x = log(2,x) = log(x)/log(2)
log(2,(x-6)) = log(x-6)/log(2)

So,
(log(x)/log(2)) + (log(x-6)/log(2)) = 4
(log(8)/log(2)) + (log(8-6)/log(2)) = 4
(log(8)/log(2)) + (log(2)/log(2)) = 4
(log(2^3)/log(2)) + (log(2)/log(2)) = 4
(3*log(2)/log(2)) + (log(2)/log(2)) = 4
3+1 = 4
4 = 4
The answer is confirmed

5 0
3 years ago
What is 8 3/5 + 4 4/5?
dangina [55]

Answer:

67/5 = 13 2/5

Step-by-step explanation:

Step 1: <u>Define/explain.</u>

An easier way to solve this is by changing the mixed fractions to improper fractions.

To do this, multiply the whole number by the denominator, then add the product to the numerator; the denominator remains the same.

Mixed fraction - a fraction with a whole number.

Improper fraction - a fraction with a numerator larger than the denominator.

Step 2: <u>Solve.</u>

8\frac{3}{5} =\frac{43}{5}

4\frac{4}{5} =\frac{24}{5}

From here, add as usual.

\frac{43}{5} +\frac{24}{5} =\frac{67}{5}

Step 3: <u>Conclude.</u>

You can change the improper fraction to a mixed fraction if you'd like.

To do this, divide the numerator by the denominator.

The amount of times the numerator evenly goes into the denominator is the whole number.

The amount of remaining numbers in the denominator.

The numerator remains the same.

\frac{67}{5} =13\frac{2}{5}

I, therefore, believe the answer to this is 13 2/5.

5 0
2 years ago
19.25 divided by 3.5
Colt1911 [192]

Answer:

It would be 5.5

for a better understanding, look it up on google

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3 years ago
How do I graph y = 9x?
Sliva [168]
Slope intercept form is y=mx+b. since there is no b term, the y intercept is 0. since there is a 9 in the m term, your slope will be nine. based on those two things, you need a point at (0,0) and (1,9). on the other end, your point will be (-1,-9). then draw a straight line through. hope this helps :)
5 0
2 years ago
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Answer:

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