Answer:
. We assume, that the number 260 is 100% - because it's the output value of the task.
2. We assume, that x is the value we are looking for.
3. If 260 is 100%, so we can write it down as 260=100%.
4. We know, that x is 6.75% of the output value, so we can write it down as x=6.75%.
5. Now we have two simple equations:
1) 260=100%
2) x=6.75%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
260/x=100%/6.75%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for what is 6.75% of 260
260/x=100/6.75
(260/x)*x=(100/6.75)*x - we multiply both sides of the equation by x
260=14.814814814815*x - we divide both sides of the equation by (14.814814814815) to get x
260/14.814814814815=x
17.55=x
x=17.55
now we have:
6.75% of 260=17.55
Step-by-step explanation:
Answer:
x = y/12
Step-by-step explanation:
The first one is: √ 96/8=2 √ 3
I might not know the answer to this question but I hope you find one
Answer:
The correct options are: Interquartile ranges are not significantly impacted by outliers. Lower and upper quartiles are needed to find the interquartile range. The data values should be listed in order before trying to find the interquartile range. The option Subtract the lowest and highest values to find the interquartile range is incorrect because the difference between lowest and highest values will give us range. The option A small interquartile range means the data is spread far away from the median is incorrect because a small interquartile means data is nor spread far away from the median
