Answer:
Maggie spent =30
Karen spent = 10
Jasmine spent =20
Step-by-step explanation:
In this we use algebra to solve.we give the sisters unknowns, to help us solve the equation.
we dont know how much jasmine used so we give her the unknown x.you can use any letter but ill us x.
karen used half as much as karen so we give her 1/2x because it was half of jasmine.maggie used 3 times that of karen so w give her 3(1/2x).
maggie =3(1/2x)
Karen =1/2x
jasmine =x
3(1/2x) + 1/2x + x = 60
3/2x + 1/2x + x = 60
2x + x = 60
3x=60
x=20
where we have x =we replace with 20
e.g karen 1/2x => 1/2 x 20 =10
if you need any clarifications please do tell me in the comment section.i would like to help more if you need help.thx
Hope this helps and if it does mark as branliest anwer thx
Answer and expl
anation is in a file. Link below. Good luck!
bit.ly/3a8Nt8n
Good morning from Canada!
What we know:
-quire=25 sheets
-ream=100 sheets
So, we are looking for how many quires can fit into a ream. All we have to do is divide the number of sheets in a ream (100) by the number of sheets in a quire (25) because dividing allows us to see how many times a specific number can go into another number, which is what we are looking for. (How many quires are in a ream).
100/25=4
Therefore 4 quires can fit into a ream.
Hope this helps!
Answer:
y = 2cos5x-9/5sin5x
Step-by-step explanation:
Given the solution to the differential equation y'' + 25y = 0 to be
y = c1 cos(5x) + c2 sin(5x). In order to find the solution to the differential equation given the boundary conditions y(0) = 1, y'(π) = 9, we need to first get the constant c1 and c2 and substitute the values back into the original solution.
According to the boundary condition y(0) = 2, it means when x = 0, y = 2
On substituting;
2 = c1cos(5(0)) + c2sin(5(0))
2 = c1cos0+c2sin0
2 = c1 + 0
c1 = 2
Substituting the other boundary condition y'(π) = 9, to do that we need to first get the first differential of y(x) i.e y'(x). Given
y(x) = c1cos5x + c2sin5x
y'(x) = -5c1sin5x + 5c2cos5x
If y'(π) = 9, this means when x = π, y'(x) = 9
On substituting;
9 = -5c1sin5π + 5c2cos5π
9 = -5c1(0) + 5c2(-1)
9 = 0-5c2
-5c2 = 9
c2 = -9/5
Substituting c1 = 2 and c2 = -9/5 into the solution to the general differential equation
y = c1 cos(5x) + c2 sin(5x) will give
y = 2cos5x-9/5sin5x
The final expression gives the required solution to the differential equation.
For this case we have the expression:
"the square root of 4" is represented algebraically as:
Then, we can express the given statement as:
They are similar terms, we can subtract:
By definition of power properties we have that:
![\sqrt [n] {a ^ n} = a ^ {\frac {n} {n}} = a](https://tex.z-dn.net/?f=%5Csqrt%20%5Bn%5D%20%7Ba%20%5E%20n%7D%20%3D%20a%20%5E%20%7B%5Cfrac%20%7Bn%7D%20%7Bn%7D%7D%20%3D%20a)
Then the expression is reduced to:
Answer:
