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Marta_Voda [28]
3 years ago
9

Which is true about the degree of the sum and difference of the polynomials 3x5y – 2x3y4 – 7xy3 and –8x5y + 2x3y4 + xy3?

Mathematics
2 answers:
Anit [1.1K]3 years ago
7 0

Answer:

The sum has a degree of 6, but the difference has a degree of 7.

Step-by-step explanation:

tankabanditka [31]3 years ago
6 0

Answer:

The option " The sum has degree of 6 , but the difference has a degree of 7 " is correct.

Step-by-step explanation:

Given that the sum and difference of the polynomials 3x^5y-2x^3y^4-7xy^3 and -8x^5y+2x^3y^4+xy^3

<h3>Now sum the given polynomials :</h3>

3x^5y-2x^3y^4-7xy^3+(-8x^5y+2x^3y^4+xy^3)

=3x^5y-2x^3y^4-7xy^3-8x^5y+2x^3y^4+xy^3

=-5x^5y+0-6xy^3

=-5x^5y-6xy^3

Therefore 3x^5y-2x^3y^4-7xy^3+(-8x^5y+2x^3y^4+xy^3)=-5x^5y-6xy^3

In the simplified <u>sum of the polynomials</u> -5x^5y-6xy^3  we have <u>the degree is 6</u>

<h3>Now difference the polynomials </h3>

3x^5y-2x^3y^4-7xy^3-(-8x^5y+2x^3y^4+xy^3)

=3x^5y-2x^3y^4-7xy^3+8x^5y-2x^3y^4-xy^3

=11x^5y-4x^3y^4-8xy^3

Therefore 3x^5y-2x^3y^4-7xy^3-(-8x^5y+2x^3y^4+xy^3)=11x^5y-4x^3y^4-8xy^3

In the simplified <u>difference of polynomials</u> 11x^5y-4x^3y^4-8xy^3 we have <u>the degree is 7</u>

Therefore the option " The sum has degree of 6 , but the difference has a degree of 7 " is correct

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Option B.

Step-by-step explanation:

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TiliK225 [7]

Solving the expression  \frac{0.5x+7}{3}=\frac{21}{4} we get: x=\frac{35}{2}\,\,or\,\,x=17.5

Step-by-step explanation:

Solving the expression: \frac{0.5x+7}{3}=\frac{21}{4}

Solving by cross multiplying:

\frac{0.5x+7}{3}=\frac{21}{4}\\(0.5x+7)*4=21*3\\Simplifying:\\2x+28=63\\Adding\,\,-28\,\,on\,\,both\,\,sides:\\2x+28-28=63-28\\2x=35\\Divide\,\,both\,\,sides\,\,by\,\,2\\\frac{2x}{2}=\frac{35}{2}\\x=\frac{35}{2}\,\,or\,\,x=17.5

So, solving the expression  \frac{0.5x+7}{3}=\frac{21}{4} we get: x=\frac{35}{2}\,\,or\,\,x=17.5

Keywords: Solving Fractions

Learn more about Solving fractions at:

  • brainly.com/question/2456302
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#learnwithBrainly

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