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Marta_Voda [28]
3 years ago
9

Which is true about the degree of the sum and difference of the polynomials 3x5y – 2x3y4 – 7xy3 and –8x5y + 2x3y4 + xy3?

Mathematics
2 answers:
Anit [1.1K]3 years ago
7 0

Answer:

The sum has a degree of 6, but the difference has a degree of 7.

Step-by-step explanation:

tankabanditka [31]3 years ago
6 0

Answer:

The option " The sum has degree of 6 , but the difference has a degree of 7 " is correct.

Step-by-step explanation:

Given that the sum and difference of the polynomials 3x^5y-2x^3y^4-7xy^3 and -8x^5y+2x^3y^4+xy^3

<h3>Now sum the given polynomials :</h3>

3x^5y-2x^3y^4-7xy^3+(-8x^5y+2x^3y^4+xy^3)

=3x^5y-2x^3y^4-7xy^3-8x^5y+2x^3y^4+xy^3

=-5x^5y+0-6xy^3

=-5x^5y-6xy^3

Therefore 3x^5y-2x^3y^4-7xy^3+(-8x^5y+2x^3y^4+xy^3)=-5x^5y-6xy^3

In the simplified <u>sum of the polynomials</u> -5x^5y-6xy^3  we have <u>the degree is 6</u>

<h3>Now difference the polynomials </h3>

3x^5y-2x^3y^4-7xy^3-(-8x^5y+2x^3y^4+xy^3)

=3x^5y-2x^3y^4-7xy^3+8x^5y-2x^3y^4-xy^3

=11x^5y-4x^3y^4-8xy^3

Therefore 3x^5y-2x^3y^4-7xy^3-(-8x^5y+2x^3y^4+xy^3)=11x^5y-4x^3y^4-8xy^3

In the simplified <u>difference of polynomials</u> 11x^5y-4x^3y^4-8xy^3 we have <u>the degree is 7</u>

Therefore the option " The sum has degree of 6 , but the difference has a degree of 7 " is correct

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Answer:

2y + 3y + x = 180 \\ 5y + 30 = 180  \\ 5y = 180 - 30 \\ 5y = 150 \\ y = 30

QOR =3Y

=3×30

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FIND THE PERCENT DECREASE FROM 20 TO 17. round to nearest tenth if necessary.<br><br> give formula
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Answer:

The percentage decrease is 15%.

Step-by-step explanation:

To find the percent decrease of any two numbers, subtract the numbers and divide it by the original.

So in this case:

20-17÷20

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What would be the equation for #23???
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Please answer this question I need this urgent Help meeeee
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Answer:

\frac{s}{2t}

Step-by-step explanation:

When you have exponents above a like term and they are being multiplied together, you add them.

For example:

a^{x} *a^{y} = a^{x + y}

So let's group like terms in the numerator:

4r^{3} r^{-5} s^{-2} s^{-1}t   We can add terms like in the example.

4 r^{-2} s^{-3} t

Let's rearrange the denominator.

8r^{-2} s^{-4} t^{2}

Now we have:

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4/8 = 1/2    

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t / t^{2}  = 1/t

Now we combine everything back together:

\frac{s}{2t}

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