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3 years ago

A and B are mutually exclusive events. P(A) = 0.60 and P(B) =0.20. What is P(A or B)?

Mathematics

1 answer:

kipiarov [429]3 years ago

5 0

Answer:

As they are mutually exclusive events so

P(A) = 0.60

P(B) = 0.20

p(A or B) = P(A) + P(B)

= 0.60 + 0.20

= 0.80

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$\frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

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How many 5-tuples of integers $(h, i, j, k,m)$ are there such that $n\ge h\ge i\ge j\ge k\ge m\ge 1$

From the question, the order of the integers h, i, j, k and m does not matter. This implies that, we make use of combination to solve this problem.

Also considering that repetition is allowed: This implies that, a number can be repeated in more than 1 location

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$^{n + 4}C_5 = \frac{(n+4)!}{(n-1)!5!}$

Expand the numerator

$^{n + 4}C_5 = \frac{(n+4)!(n+3)*(n+2)*(n+1)*n*(n-1)!}{(n-1)!5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5*4*3*2*1}$

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