HELP ME PLEASE!!<br> Its just one question!!

hey i know this may be a lame question but can anyone help me how can i multiply 16 with 3,142 (with steps) ?? :/

vovangra [49]

Answer:

50272

Step-by-step explanation:

Okay how I solve these equations is I take the problem apart like this:

3142 = 3000 + 100 + 40 + 2

Now we multiply each number by 16:

3000 * 16 = 48000

100 * 16 = 1600

40 * 16 = 640

2 * 16 = 32

Then we add all the totals together:

48000 + 1600 + 640 + 32 = 50272

Hope this Helps ;)

8 0

2 years ago

Can someone help me with these questions ? 15-21 <br> It’s due today and i really need help...

Darya [45]

Answer:

15-21=(-6)

Step-by-step explanation:

4 0

2 years ago

X^2 + y^2 = 81 write down the equations of the two horizontal lines that are tangent to c

Inessa [10]

Answer:

Step-by-step explanation:

x² + y² = 81

x + y = √81

x + y = 9

x ≥ 9

y ≤ 9

6 0

1 year ago

A box has twice as many grapes as a basket. Once 2kg of grapes were added to the basket, it contained 0.5 kg more than the box.

pav-90 [236]

By solving a system of equations, we will see that now there are 3.5kg of grapes on the basket.

<h3>How many kilograms of grapes are in the basket now?</h3>

Let's define the variables:

x = kg of grapes on the box originally.
y = kg of grapes on the basket originally.

We know that:

x = 2y

When we add 2kg to the basket, it has 0.5k more than the box, then:

y + 2 = x + 0.5

Then we have a system of equations:

x = 2y

y + 2 = x + 0.5

We want to solve this for y, then we can replace the first equation into the second one:

y + 2 = (x = 2y) + 0.5

y + 2 = 2y + 0.5

2 - 0.5 = 2y - y

1.5 = y

This means that, originally, there are 1.5 kg of grapes on the basket. And then we added 2kg, so now there are:

1.5kg + 2kg = 3.5kg

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

3 0

1 year ago

Cable Strength: A group of engineers developed a new design for a steel cable. They need to estimate the amount of weight the ca

KatRina [158]

Answer:

95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

Step-by-step explanation:

We are given that the engineers take a random sample of 45 cables and apply weights to each of them until they break. The mean breaking weight for the 45 cables is 768.2 lb. The standard deviation of the breaking weight for the sample is 15.1 lb.

Since, in the question it is not specified that how much confidence interval has be constructed; so we assume to be constructing of 95% confidence interval.

Firstly, the Pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean breaking weight = 768.2 lb

s = sample standard deviation = 15.1 lb

n = sample of cables = 45

$\mu$ = population mean breaking strength

Here for constructing 95% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

<u>So, 95% confidence interval for the population mean, </u> $\mu$ <u> is ;</u>

P(-2.02 < $t_4_4$ < 2.02) = 0.95 {As the critical value of t at 44 degree

of freedom are -2.02 & 2.02 with P = 2.5%}

P(-2.02 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.02) = 0.95

P( $-2.02 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.02 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.02 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.02 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

<u>95% confidence interval for</u> $\mu$ = [ $\bar X-2.02 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.02 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $768.2-2.02 \times {\frac{15.1}{\sqrt{45} } }$ , $768.2+2.02 \times {\frac{15.1}{\sqrt{45} } }$ ]

= [763.65 lb , 772.75 lb]

Therefore, 95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

3 0

2 years ago

HELP ME PLEASE!! Its just one question!!