Answer: C) A pair of intersecting lines
Step-by-step explanation: The three types of degenerate conic sections are a point, a line, and a pair of intersecting lines.
I hope this helps!
A= lw
I'd convert fractions improper fractions
117/4= 3/2l (length)
l = 117/4 / 3/2
Turn 3/2 upside down n multiply them;
117/4 x 2/3 = 234/12 = 19 1/2 is the length
We are given that it takes 7 joules of heat to raise the
temperature of the bar by 1°C. Therefore this means that the heating capacity Cp
is:
Cp = 7 J / °C
The formula for the amount of heat required is:
heat = Cp (Tf – Ti)
where Ti is initial temperature = 25°C, and Tf is the
final temperature
When Tf = 26°C
heat = 7 (26 – 25) = 7 J
When Tf = 27°C
heat = 7 (27 – 25) = 14 J
When Tf = 28°C
heat = 7 (28 – 25) = 21 J
When Tf = 29°C
heat = 7 (29 – 25) = 28 J
When Tf = 30°C
heat = 7 (30 – 25) = 35 J
When Tf = 35°C
heat = 7 (35 – 25) = 70 J
Answer:
A = 57°
B = 19°
C = 104°
Step-by-step explanation:
We have a triangle with 3 angles:
A, B, and C.
We know that:
"Angle A is 3 times larger than angle B"
We can write this as:
A = 3*B
"Angle C was 10° less than 6 times angle B"
This can be written as:
C = 6*B - 10°
And we also know that the sum of all interior angles of a triangle is 180°
Then we also have the equation:
A + B + C = 180°
So we have a system of 3 equations:
A = 3*B
C = 6*B - 10°
A + B + C = 180°
To solve this, the first step is to isolate one of the variables in one of the equations.
We can see that A is already isolated in the first one, so we can skip that step.
Now we need to replace A in the other equations, to get:
C = 6*B - 10°
(3*B) + B + C = 180°
Now we have a system of two equations.
Let's do the same procedure, we can see that C is isolated in the top equation, so we can just replace that in the other equation to get:
3*B + B + (6*B - 10°) = 180°
Now we can solve this for angle B
4*B + 6*B - 10° = 180°
10*B - 10° = 180°
10*B = 180° + 10° = 190°
B = 190°/10 = 19°
Now that we know the measure of angle B, we can input this in the equations:
A = 3*B
C = 6*B - 10°
To find the measures of the other two angles:
A = 3*19° = 57°
C = 6*19° - 10° = 104°