All categories

3 years ago

How many two digit positive integers can be formed from the digits 1, 3, 5, and 9, if no digit is repeated?

Mathematics

2 answers:

ruslelena [56]3 years ago

8 0

Answer:

12 two digit positive integers can be formed

Step-by-step explanation:

Find the number of two digit positive integers can be fromed from the digits 1, 3, 5, and 9, if no digit is repeated

we are given with 1,3,5 and 9 that is 4 numbers

we need to frame a two digit positive integer

First digit uses all the 4 numbers

second digit use the remaining 3 numbers

So 4* 3= 12 two digit positive integers can be formed

Masja [62]3 years ago

5 0

The answer is 12

All possible units are 13, 15, 19, 31, 35, 39, 51, 53, 59, 91, 93, 95

You might be interested in

Please Help me with this question. Will give Brainllest

Wewaii [24]

Answer:63

Step-by-step explanation:

7 0

3 years ago

Do not understand!!!!!

Nadya [2.5K]

The answer to this equation is 2

7 0

3 years ago

The area of a square in square feet is

Sedaia [141]

Answer:

Part 1) The expression for the perimeter is $P=4(25z-3)$ or $P=100z-12$

Part 2) The perimeter when z = 15 ft. is $P=1,488\ ft$

Step-by-step explanation:

Part 1)

we have

$625z^{2}-150z+9$

Find the roots of the quadratic equation

Equate the equation to zero

$625z^{2}-150z+9=0$

Complete the square

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$625z^{2}-150z=-9$

Factor the leading coefficient

$625(z^{2}-(150/625)z)=-9$

$625(z^{2}-(6/25)z)=-9$

Complete the square. Remember to balance the equation by adding the same constants to each side

$625(z^{2}-(6/25)z+(36/2,500))=-9+(36/4)$

$625(z^{2}-(6/25)z+(36/2,500))=0$

Rewrite as perfect squares

$625(z-6/50)^{2}=0$

$z=6/50=0.12$ -----> root with multiplicity 2

The area is equal to

$A=625(z-0.12)(z-0.12)=[25(z-0.12)][25(z-0.12)]=(25z-3)^{2}$

The length side of the square is $b=(25z-3)$

therefore

The perimeter is equal to

$P=4b$

$P=4(25z-3)$

$P=100z-12$

Part 2) Find the perimeter when z = 15 ft.

we have

$P=100z-12$

substitute the value of z

$P=100(15)-12=1,488\ ft$

4 0

3 years ago

If you deposit $1000 in a savings account with an interest rate of r compounded annually, then the balance in the account after

Sedaia [141]

Answer:

Step-by-step explanation:

Our equation is as follows, B(c)=1000(1+r)^3. We are being asked to manipulate the equation and have it be r equals in order to solve for an interest rate when given a balance B. To solve the equation for the variable r, we must isolate r by completing order of operations or PEMDAS backwards.

SADMEP allows us to undo subtraction, addition, and etc in the correct order. We have no subtraction or addition outside of more complex operations. So we move to multiplication or division.

We divide both sides by 1000.

$\frac{B}{1000} =\frac{1000(1+r)^{3} }{1000}$