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777dan777 [17]
3 years ago
8

!00000 times 62 Go sub to my bros yt keditoplayz

Mathematics
2 answers:
Ksju [112]3 years ago
6 0

eidjejjxjfjrjkajzifjfnkdownd

belka [17]3 years ago
4 0

Answer:

v4vn mrhnme

Step-by-step explanation:

You might be interested in
For the following exercises, evaluate the function f at the values f(−2), f(−1), f(0), f(1), and f(2)
MatroZZZ [7]

Answer:

See below.  <u><em>I assume that (x) = 8x2 - 7x + 3 is really (x) = 8x^2 - 7x + 3</em></u>

Step-by-step explanation:

Substitute the value of x given in f(x) into the equation f(x) = 8x^2 - 7x + 3

For example, f(0) would be f(0) = 8(0)^2 - 7(0) + 3.  f(0) = 3

f(-2) would be f(-2) = 8(-2)^2 - 7(-2) + 3.  

                                =   8*4  + 14 +3

                                = 32 + 17        therefore      f(-2) = 49

<u>x</u> <u>f(x)</u>

-2 49

-1 18

0 3

1 4

2 21

4 0
2 years ago
Grace uses 9.8 pints of blue paint and white paint to paint her bedroom walls. 4/5
igor_vitrenko [27]
4/5 * 9.8 = 7.84 pints of blue paint
9.8 - 7.84 = 1.96 pints of white paint
5 0
3 years ago
What is 3/4 times 8/3 i need a correct
bija089 [108]
2 would be the correct answer:)

6 0
3 years ago
Read 2 more answers
Help please i’m not really sure what the answer is
Maslowich

Answer:

The area is 48

The perimeter is 32

4 0
3 years ago
Can someone please help me??
dmitriy555 [2]

Answer:

I is clear that, the linear equation 5x+12=5x-7 has no solution.

Step-by-step explanation:

<u>Checking the first option:</u>

\frac{2}{3}\left(9x+6\right)=6x+4

6x+4=6x+4

\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}

6x+4-4=6x+4-4

6x=6x

\mathrm{Subtract\:}6x\mathrm{\:from\:both\:sides}

6x-6x=6x-6x

0=0

\mathrm{Both\:sides\:are\:equal}

\mathrm{True\:for\:all}\:x

<u>Checking the 2nd option:</u>

5x+12=5x-7

\mathrm{Subtract\:}5x\mathrm{\:from\:both\:sides}

5x+12-5x=5x-7-5x

\mathrm{Simplify}

12=-7

\mathrm{The\:sides\:are\:not\:equal}

\mathrm{No\:Solution}

<u>Checking the 3rd option:</u>

4x+7=3x+7

\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}

4x+7-7=3x+7-7

\mathrm{Simplify}

4x=3x

\mathrm{Subtract\:}3x\mathrm{\:from\:both\:sides}

4x-3x=3x-3x

\mathrm{Simplify}

x=0

<u>Checking the 4th option:</u>

-3\left(2x-5\right)=15-6x

\mathrm{Subtract\:}15\mathrm{\:from\:both\:sides}

-6x+15-15=15-6x-15

\mathrm{Simplify}\

-6x=-6x

\mathrm{Add\:}6x\mathrm{\:to\:both\:sides}

-6x+6x=-6x+6x

\mathrm{Simplify}

\mathrm{Both\:sides\:are\:equal}

\mathrm{True\:for\:all}\:x

Result:

Therefore, from the above calculations it is clear that, the linear equation

5x+12=5x-7 has no solution.

4 0
3 years ago
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