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tatyana61 [14]
2 years ago
13

62% of salmon pass through a single dam unharmed. By what percent does the number of salmon decrease when passing through a sing

le dam?
Mathematics
1 answer:
Vlad [161]2 years ago
6 0

Answer: 38% of fish decrease when passing through a single dam

Step-by-step explanation: you would take 100% - 62% which equals 38%

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(c) a farm brings 15 tons of watermelon to market. find a 90% confidence interval for the population mean cash value of this cro
Nina [5.8K]

Answer:

First we need to name some of the variables we are given:n = 38 the sample sizex = 6.88 the sample mean = 1.86 the population standard deviationWe need to find a 90% confidence interval for the mean price per 100 lbs of watermelon: = 1-.90 = .10/2 = .05z(/2) = -1.64-z(/2) = 1.64This can give us a probability expression:P(-1.645 < z < 1.645) = .90The margin of error is calculated with the formula: E = z(/2)(/√n)E = 1.645(1.86/√38) = $.4963(300) = $148.89   Then to calculate the upper and lower limit we add and subtract E from x:lower limit = 6.88 - .4963 = $7.38(300) = $2214upper limit = 6.88 + .4963 = $6.38(300) = $1914Note: We multiply the E, upper and lower limits by 300 because 15 tons is 30000lbs and we need the price per 100 lbs, so we divide 30000/100 and get 300.

Step-by-step explanation:

7 0
2 years ago
Find the sum of the convergent series 7 0.7 0.007
mafiozo [28]
7+0.7+0.007+\cdots=7\left(1+\dfrac1{10}+\dfrac1{100}+\cdots\right)

Let S_n denote the nth partial sum of the series, i.e.

S_n=1+\dfrac1{10}+\dfrac1{100}+\cdots+\dfrac1{100^n}

Then

\dfrac1{10}S_n=\dfrac1{10}+\dfrac1{100}+\dfrac1{1000}+\dfrac1{10^{n+1}}

and subtracting from S_n we get

S_n-\dfrac1{10}S_n=\dfrac9{10}S_n=1-\dfrac1{10^{n+1}}
\implies S_n=\dfrac{10}9\left(1-\dfrac1{10^{n+1}}\right)

As n\to\infty, the exponential term vanishes, leaving us with

\displaystyle\lim_{n\to\infty}S_n=\dfrac{10}9

and so

7+0.7+0.007+\cdots=7.777\ldots=\dfrac{70}9
3 0
3 years ago
The height of a ball above the ground in feet is defined by the function h(t) = -16t Squared + 80t +3, where t is the number of
jasenka [17]
Plug in 2 for t.
=> -16*(2^2) +80*2 +3
=> -16*4 +160 +3
=> -64+163
=> 99
6 0
3 years ago
Approximate the real zeros of f(x)= 2x^3 - 4x^2 - 3 to the nearest tenth.
Scrat [10]

Answer:

b.2.3

Step-by-step explanation:

f(x)= 2x^3 - 4x^2 - 3

see graph below

only x intercept is 2.287

6 0
3 years ago
Please answer ASAP. Will reward Brainliest Answer to first, correct answer, with explanation!
Vsevolod [243]

Answer:

1.C

2.A

3.D

4.C

5.B

6.A


Step-by-step explanation:


3 0
3 years ago
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