Distance to travel = 20 m.
Let us determine the time, t, that each participant took to complete 20 m.
Barbara:
Average speed = (3 m)/(2 s) = 1.5 m/s
t = 20/1.5 = 13.3 s
Mark:
t = 5 s
Carlos:
y = x + 1
where
y = 20 m
x = time, t
Therefore
t =x = y - 1 = 20 - 1 = 19 s
Summary:
Barbara: 13.3 s
Mark: 5 s
Carlos: 19 s
Answer:
The winner is Mark
For this one I'm going to assume that 4 7a means 4 * 7a...
(8 + 7a) + 4 * 7a =
8 + 7a + 28a =
8 + 35a
If I read it wrong and 4 7a is actually 47a then...
(8 + 7a) + 47a =
8 + 54a =
2(4 + 27a)
T_n = 3 * T_(n-1)
Long way (always works!)
T_5 = 3*T_4,
T_4 = 3*T_3
T_3 = 3*T_2
T_2 = 3*T_1
T_5 = 3*3*3*3*T_1 = 81*T_1 = 81*8 = 648!
Short way (sometimes it works!)
T_n = 3^(n-1) * T_1 (this case is a geometric series of ratio-=3)
T_5 = 3^4*8 = 648
The period of the function is 2pi
Answer:
m= 4.5 miles
Step-by-step explanation:
Let the number of miles Evelyn can run be m and can be modeled by the equation below
m= kx
Where x Is the Minutes
When m= 3
x= 40
3= k40
k= 3/40
If x= 60
m=3/40(60)
m = (60*3)/40
m= 180/40
m= 4.5 miles
