Answer:
S(t) = 600*0.9^t
Step-by-step explanation:
At the beginning (t = 0) the sample has 600 grams. After 1 millennium from today (t = 1) the mass will be: 600 - 600*0.1 = 600*0.9. After 2 millennium from today (t = 2) the mass will be the 90% of the mass in the previous millenium, that is: 600*0.9*0.9 = 600*0.9^2. Analogously, at time = 3, sample's mass will be: 600*0.9^2*0.9 = 600*0.9^3. In a table format, that is
t m
0 600
1 600 - 600*0.1 = 600*0.9
2 600*0.9*0.9 = 600*0.9^2
3 600*0.9^2*0.9 = 600*0.9^3
Therefore, sample's mass in grams, S(t), where t refers to millennia from today is computed as follows: S(t) = 600*0.9^t
Answer:
Follow the followings steps to draw a quadrilateral with 4 unequal sides:
Step 1 : Draw line
of length 10cm.
Step 2 : Construct 90° angle on
with A as vertex and mark an arc of 5 cm on new arm of right angle. That's Point D.
Step 3 : Again Construct 90° angle on
with D as vertex.
Step 4 : Mark an arc of length 6 cm on arm of 2nd right angle. Mark that point as C.
Step 5 : To complete the Quadrilateral, Join Point C and B.
A Quadrilateral (Specially mentioned Trapezoid) ABCD with four unequal side is constructed.
Answer:
7 dogs
Step-by-step explanation:
$30/3 = how many dollars per dog
$10 per dog he washes
$70/$10 = 7, he washes 7 dogs
Answer:
It is not reasonable that the state education department claims the percentage for the entire state is 73%.
Step-by-step explanation:
We are given that 191 of the 288 high school students surveyed at a local school said they went outside more during school hours as elementary school students than they do now as high school students.
Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;
P.Q. =
~ N(0,1)
where,
= sample proportion of high school students who went outside more during school hours as elementary school students than they do now as high school students =
= 0.66
n = sample of high school students = 288
p = population percentage for the entire state
<em>
Here for constructing a 90% confidence interval we have used a One-sample z-test for proportions.
</em>
<em>
</em>
The margin of error is given by;
M.E. = 
= 
M.E. = 0.056 or 5.6%
So, the confidence interval so formed = 
= [
]
= [0.604, 0.716]
Since the above interval does not include 0.73 or the population proportion of 73% falls outside the above interval. So, it is not reasonable that the state education department claims the percentage for the entire state is 73%.
What is the figure?.......