Answer:
33.94 cms of ribbon
Step-by-step explanation:
Because you need two diagonals to form the x, therefore the amount of ribbon needed is the sum of the distance of both diagonals.
When crossing the diagonal, a rectangular angle is formed, where the diagonal would be the hypotenuse, we know that the distance of the hypotenuse can be calculated by means of the legs, which we know its value (12):
d ^ 2 = a ^ 2 + b ^ 2
a = b = 12
d ^ 2 = 12 ^ 2 + 12 ^ 2
d ^ 2 = 288
d = 288 ^ (1/2)
d = 16.97
16.97 cm is what it measures, a diagonal, therefore tape is needed:
16.97 * 2 = 33.94
A total of 33.94 cms of ribbon is needed
Answer from jmonterrozar
Answer:

Step-by-step explanation:
The length of a chalkboard, l = 1.7
The width of a chalkboard, b = 0.9 m
We need to find the area of the chalkboard. The formula for the area of a rectangle is given by :

So, the area of the chalkboard is equal to
.
Answer:
x = 3/2
Step-by-step explanation:
Step 4: 2x + 8 = 11
step 5: 2x +8 - 8 = 11 -8
step 6: 2x/2 = 3/2
step 7: <u>x = 3/2</u>
(0,0) represents the very beginning of the rental period: 0 time has elapsed, and thus there is no charge.
(1,125) represents this situation 1 hour after the rental has begun, and shows that the amount due at that point for the rental is
$125.
Answer:
-2
Step-by-step explanation:
If we have an equation of the form y = mx +b then the y-intercept is b.
So now here we have y =-x - 2. Therefore b = -2 and we conclude the y-intercept is -2.